分区上的递归CTE或ROW_NUMBER？

Question

嗨下面是一个小样本，我试图通过CDO_OP_REFERRAL_UNIQUE_ID找到一种基于ATTENDED_OR_DID_NOT_ATTEND重置COUNT的方法，最后一列是我不能在查询中应用的预期结果，每次我使用ROW_NUMBER而不是分区我保持每次ATTENDED_OR_DID_NOT_ATTEND更改时都不会再次重新启动

DECLARE @CDO_OP_APPOINTMENT TABLE (CDO_OP_REFERRAL_UNIQUE_ID int,LOCAL_PATIENT_NUMBER varchar(10),APPOINTMENT_START_DATE_TIME datetime,ATTENDED_OR_DID_NOT_ATTEND varchar(10),DESIRED_OUTCOME varchar(10))

INSERT INTO @CDO_OP_APPOINTMENT

VALUES

('480805568',   'HEY1030785',   '05/11/2013 10:00', '2',    '1'),
('480805568',   'HEY1030785',   '12/11/2013 10:00', '5',    '1'),
('480805568',   'HEY1030785',   '22/11/2013 09:30', '5',    '2'),
('480805568',   'HEY1030785',   '03/12/2013 13:00', '3',    '1'),
('480805568',   'HEY1030785',   '30/12/2013 10:15', '5',    '1'),
('480805568',   'HEY1030785',   '24/02/2014 09:15', '4',    '1'),
('480805568',   'HEY1030785',   '24/02/2014 14:15', '5',    '1'),
('480805568',   'HEY1030785',   '17/03/2014 15:25', '4',    '1'),
('480805568',   'HEY1030785',   '20/03/2014 18:50', '5',    '1'),
('480805568',   'HEY1030785',   '23/09/2014 15:55', '5',    '2'),
('480805568',   'HEY1030785',   '14/04/2015 16:30', '5',    '3'),
('480805568',   'HEY1030785',   '14/04/2015 17:30', '4',    '1'),
('480805568',   'HEY1030785',   '15/05/2015 14:15', '5',    '1')

SELECT * from @CDO_OP_APPOINTMENT

Answer 1

这是一个间隙和岛屿问题。最简单的解决方案是行数的差异：

select a.*,
       row_number() over (partition by CDO_OP_REFERRAL_UNIQUE_ID, ATTENDED_OR_DID_NOT_ATTEND , seqnum - seqnum_2 order by APPOINTMENT_START_DATE_TIME) as desired_result
from (select a.*,
             row_number() over (partition by CDO_OP_REFERRAL_UNIQUE_ID order by APPOINTMENT_START_DATE_TIME) as seqnum,
             row_number() over (partition by CDO_OP_REFERRAL_UNIQUE_ID, ATTENDED_OR_DID_NOT_ATTEND order by APPOINTMENT_START_DATE_TIME) as seqnum_2,
      from @CDO_OP_APPOINTMENT a
     ) a;

Answer 2

管理解决非常类似上面的答案

set dateformat dmy
go

DECLARE @CDO_OP_APPOINTMENT TABLE (CDO_OP_REFERRAL_UNIQUE_ID int,LOCAL_PATIENT_NUMBER varchar(10),APPOINTMENT_START_DATE_TIME datetime,ATTENDED_OR_DID_NOT_ATTEND varchar(10),DESIRED_OUTCOME varchar(10))

INSERT INTO @CDO_OP_APPOINTMENT

VALUES

('480805568',   'HEY1030785',   '05/11/2013 10:00', '2',    '1'),
('480805568',   'HEY1030785',   '12/11/2013 10:00', '5',    '1'),
('480805568',   'HEY1030785',   '22/11/2013 09:30', '5',    '2'),
('480805568',   'HEY1030785',   '03/12/2013 13:00', '3',    '1'),
('480805568',   'HEY1030785',   '30/12/2013 10:15', '5',    '1'),
('480805568',   'HEY1030785',   '24/02/2014 09:15', '4',    '1'),
('480805568',   'HEY1030785',   '24/02/2014 14:15', '5',    '1'),
('480805568',   'HEY1030785',   '17/03/2014 15:25', '4',    '1'),
('480805568',   'HEY1030785',   '20/03/2014 18:50', '5',    '1'),
('480805568',   'HEY1030785',   '23/09/2014 15:55', '5',    '2'),
('480805568',   'HEY1030785',   '14/04/2015 16:30', '5',    '3'),
('480805568',   'HEY1030785',   '14/04/2015 17:30', '4',    '1'),
('480805568',   'HEY1030785',   '15/05/2015 14:15', '5',    '1')


SELECT CDO_OP_REFERRAL_UNIQUE_ID ,LOCAL_PATIENT_NUMBER ,APPOINTMENT_START_DATE_TIME ,ATTENDED_OR_DID_NOT_ATTEND 
,ROW_NUMBER() OVER (PARTITION BY CDO_OP_REFERRAL_UNIQUE_ID,Seq1-Seq2,ATTENDED_OR_DID_NOT_ATTEND ORDER BY APPOINTMENT_START_DATE_TIME) AS DESIRED_OUTCOME 
FROM
(
SELECT *,ROW_NUMBER() OVER (PARTITION BY CDO_OP_REFERRAL_UNIQUE_ID ORDER BY APPOINTMENT_START_DATE_TIME) AS Seq1,
ROW_NUMBER() OVER (PARTITION BY CDO_OP_REFERRAL_UNIQUE_ID,ATTENDED_OR_DID_NOT_ATTEND ORDER BY APPOINTMENT_START_DATE_TIME) AS Seq2

 from @CDO_OP_APPOINTMENT
 )t
 ORDER BY APPOINTMENT_START_DATE_TIME