我已经创建了一个演示网站来向客户销售产品。该网站使用过滤器/搜索/排序等来简化浏览不同产品的过程。我遇到的问题与过滤和搜索有关。我想对过滤器进行处理,使其对搜索结果有效。我已经尝试使用复选框和Vue中的计算属性进行此操作。
HTML
<div id="app">
<h5>Search</h5>
<input type="text" v-model="search" placeholder="Search title.."/><br><br>
<h5>Filter</h5>
<li v-for="filter in possibleFilters" :key="filter">
<label>
<input type="checkbox" @change="toggleFilter(filter)" :checked="filters.includes(filter)">
<span >{{filter}}</span>
</label>
</li>
<div class="block" v-for="(product, index) in filteredSearch">
<hr>
<h3>{{product.name}}</h3>
<p>Price: £{{product.price}}</p>
<p>Location: {{product.location}}</p>
<hr>
</div>
</div>
JavaScript
new Vue({
el: "#app",
data: {
filters:[],
search:"",
products: [{
name: "milk",
location: "London",
price: 100
},
{
name: "oranges",
location: "Birmingham",
price: 80
},
{
name: "apples",
location: "Edinburgh",
price: 90
},
{
name: "bananas",
location: "Paris",
price: 120
},
{
name: "bread",
location: "Paris",
price: 110
},
{
name: "water",
location: "Oslo",
price: 90
},
{
name: "soda",
location: "London",
price: 90
},
{
name: "tea",
location: "Oslo",
price: 120
},
{
name: "bakedbeans",
location: "Oslo",
price: 140
}
],
},
methods: {
toggleFilter (newFilter) {
this.filters = !this.filters.includes(newFilter)
? [...this.filters, newFilter]
: this.filters.filter(f => f !== newFilter)
}
},
computed: {
possibleFilters() {
return [...new Set(this.filteredSearch.map(x => x.location))]
},
filteredSearch() {
return this.products.filter(p => {
var searchProduct = p.name.toLowerCase().includes(this.search.toLowerCase());
var filterProduct = this.filters.length == 0 || this.filters.includes(p.location);
return searchProduct && filterProduct
})
}
},
})
问题是我不能多次选择过滤器。过滤器基于位置,我的目标是能够多次应用过滤器。目前,我一次只能选择一个过滤器。
即,如果我搜索“ l”,则返回牛奶和苹果,过滤器显示伦敦和爱丁堡,我只能选择伦敦或爱丁堡,但不能同时选择两者。如果我选择伦敦,则只应向我显示“牛奶”,同时仍向我显示“爱丁堡”选项,当我同时选择两者时,应同时向我显示“牛奶”和“苹果”
显示问题的小提琴:https://jsfiddle.net/Calv7/L1vnqh63/9/
任何帮助将不胜感激。谢谢。
这能解决您的问题吗?
possibleFilters() {
return [...new Set(this.products.map(x => x.location))]
},