更新每一个职位请求的状态

问题描述 投票:1回答:1

嘿,伙计们,我有一个表单在我的react redux项目,所以在提交表单时,我调用一个动作,点击post api插入文档到mongodb,所以我也希望是每次更新的状态,所以,只要我提交的形式,我的状态得到更新,然后我渲染他们以下(作为对象数组)。

表格.js

class Form extends Component {

  constructor(props) {
    super(props);
    this.state = {
      taskName: "",
      taskDescription: "",

    };
  }



  handleSubmit = () => {
    this.props.addTask(this.state);
  };
  render() {
    return (
      <div className="m-4">
        <div className="d-flex justify-content-between align-items-center">
          {" "}
          <h2 className=" ">Pomodoro Tasks</h2>
          <button className="btn btn-primary" onClick={()=>window.location.reload()}>Refresh</button>
        </div>
        <form>
        <div className="form-group ">
          <label>Task Name</label>
          <input
            type="text"
            className="form-control"
            onChange={(e) => this.setState({ taskName: e.target.value })}
          />
        </div>
        <div className="form-group">
          <label>Task Description</label>
          <input
            type="text"
            className="form-control"
            onChange={(e) => this.setState({ taskDescription: e.target.value })}
          />
        </div>


        </form>

        <button type="submit" className="btn btn-primary" onClick={(e) => this.handleSubmit(e)}>
          Submit
        </button>

       ////render here the state
      </div>
    );
  }
}
const mapStateToProps = (state) => {

  return state
};
export default connect(mapStateToProps, { addTask })(Form);

Actions.js

export const addTask = (details) => {
  return async (dispatch ,getState) =>{

    axios.post('/add_task', details)
      .then(function (response) {
        Swal.fire('Tasks Added !')
        dispatch({type:POSTDATA,payload:response.data})
      })
      .catch(function (error) {
        Swal.fire('Error in adding to database')
        console.log(error);
      });

  };
};

export const getTask = () => {
  return async (dispatch ,getState) =>{
    axios.get('/get_task')
      .then(function (response) {
        dispatch({type:GETDATA,payload:response.data})
      })
      .catch(function (error) {
        console.log(error);
      });
  };
};

reducer.js

const postPomodoro = (state = [], action) => {
  switch (action.type) {
    case POSTDATA:
      return action.payload; //well this is only returning one object that is inserted at that time i need to 
somehow get all the previous data too that are inserted in order to update state with all data and then render it.

    default:
      return state;
  }
};
const getPomodoro = (state = [], action) => {
  switch (action.type) {

    case GETDATA:
      return {...state,tasks:action.payload};
    default:
      return state;
  }
};

我在reducer中试了一下

 case POSTDATA:
      return {...state,task:action.payload};

但这也给了我最近的数据,被插入,而不是所有的数据,以前插入的

reactjs redux react-redux redux-thunk
1个回答
1
投票

你需要合并状态中的数据,而不是覆盖它。在你的reducer中使用一个spread语法来实现这个功能,比如下面的内容

const postPomodoro = (state = [], action) => {
  switch (action.type) {
    case POSTDATA:
      return [...state, action.payload]; 

    default:
      return state;
  }
};

一旦你在reducer中更新了状态,你就可以在组件中使用connect和mapStateToProps来访问它。

const Comp = (props) => {
   // iterate over props.postTask and render
}
const mapStateProps = (state) => {
   return {
      postTask: state.postPomodoro
   }
}
export default connect(mapStateToProps)(Comp)
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