通过select子句添加临时列不起作用？错误是期望的列少于返回的列。我发誓我早先可以使用它

Question

CREATE OR REPLACE FUNCTION get_user_info ( u_email VARCHAR, u_password VARCHAR, p_name VARCHAR )
RETURNS TABLE(
    user_id             int,                
    given_name          varchar(55),
    family_name         varchar(55),
    password            varchar(255),
    email               varchar(255),
    date_of_birth       date
)
AS $$
BEGIN
    -- If a player display player_name and team_id
    IF p_name != '' THEN
        RETURN QUERY
        SELECT player.user_id, player.given_name, player.family_name, player.password, player.email, player.date_of_birth,
        player.player_name AS player_name, player.team_id AS team_id FROM player
        WHERE player.email = u_email and player.password = u_password;
    -- If not a player then display usual table
    ELSE
        RETURN QUERY
        SELECT * FROM "user"
        WHERE "user".email = u_email and "user".password = u_password;
    END IF;
END $$
LANGUAGE plpgsql;

-- Get user info with arguments - email, password and player_name. If not a player pass '' as player_name
SELECT get_user_info('[email protected]', 'tommy12', 'tomkilla'); -- Player

错误：

ERROR:  structure of query does not match function result type
DETAIL:  Number of returned columns (8) does not match expected column count (6).
CONTEXT:  PL/pgSQL function get_user_info(character varying,character varying,character varying) line 5 at RETURN QUERY
SQL state: 42804

只是想知道为什么我会收到此错误？我发誓我早些时候可以使用它，但是现在它不> _>如果我是旁观者，则查询有效

创建或替换功能get_user_info（u_email VARCHAR，u_password VARCHAR，p_name VARCHAR）返回表（user_id int，给定名称varchar（55），...

Answer 1

您的函数期望仅返回6列