我正在尝试将时间从 12 小时制转换为 24 小时制...
06:35 ## Morning
11:35 ## Morning (If m2 is anywhere between 10:00 and 12:00 (morning to mid-day) during the times of 10:00 and 13:00 (1pm) then the m2 time is a morning time)
1:35 ## Afternoon
11:35 ## Afternoon
m2 = "1:35" ## This is in the afternoon.
m2 = datetime.strptime(m2, "%H:%M")
print m2
13:35
1900-01-01 01:35:00
我尝试了第二种变体，但再次没有帮助：/
m2 = "1:35" ## This is in the afternoon.
m2split = m2.split(":")
if len(m2split[0]) == 1:
m2 = ("""%s%s%s%s""" % ("0", m2split[0], ":", m2split[1]))
print m2
m2temp = datetime.strptime(m2, "%I:%M")
m2 = m2temp.strftime("%H:%M")
我做错了什么以及如何解决这个问题？
此方法使用 strptime 和 strftime 以及格式指令，如 https://docs.python.org/2/library/datetime.html#strftime-strptime-behavior，%H 是 24 小时时钟，%I 是12 小时制，当使用 12 小时制时，如果是 AM 或 PM，%p 符合资格。
>>> from datetime import datetime
>>> m2 = '1:35 PM'
>>> in_time = datetime.strptime(m2, "%I:%M %p")
>>> out_time = datetime.strftime(in_time, "%H:%M")
>>> print(out_time)
13:35
您需要指定您的意思是下午而不是上午。
>>> from datetime import *
>>> m2 = '1:35 PM'
>>> m2 = datetime.strptime(m2, '%I:%M %p')
>>> print(m2)
1900-01-01 13:35:00
试试这个:)
currenttime = datetime.datetime.now().time().strftime("%H:%M")
if currenttime >= "10:00" and currenttime <= "13:00":
if m2 >= "10:00" and m2 >= "12:00":
m2 = ("""%s%s""" % (m2, " AM"))
else:
m2 = ("""%s%s""" % (m2, " PM"))
else:
m2 = ("""%s%s""" % (m2, " PM"))
m2 = datetime.datetime.strptime(m2, '%I:%M %p')
m2 = m2.strftime("%H:%M %p")
m2 = m2[:-3]
print m2
13:35
如果日期采用这种格式（HH:MM:SSPM/AM），则以下代码有效：
a=''
def timeConversion(s):
if s[-2:] == "AM" :
if s[:2] == '12':
a = str('00' + s[2:8])
else:
a = s[:-2]
else:
if s[:2] == '12':
a = s[:-2]
else:
a = str(int(s[:2]) + 12) + s[2:8]
return a
s = '11:05:45AM'
result = timeConversion(s)
print(result)
time = raw_input().strip() # input format in hh:mm:ssAM/PM
t_splt = time.split(':')
if t_splt[2][2:] == 'PM' and t_splt[0] != '12':
t_splt[0] = str(12+ int(t_splt[0]))
elif int(t_splt[0])==12 and t_splt[2][2:] == 'AM':
t_splt[0] = '00'
t_splt[2] = t_splt[2][:2]
print ':'.join(t_splt)
def timeConversion(s):
if "PM" in s:
s=s.replace("PM"," ")
t= s.split(":")
if t[0] != '12':
t[0]=str(int(t[0])+12)
s= (":").join(t)
return s
else:
s = s.replace("AM"," ")
t= s.split(":")
if t[0] == '12':
t[0]='00'
s= (":").join(t)
return s
试试这个😊
dicti =
{'01':13,'02':14,'03':15,'04':16,'05':17,'06':18,'07':19,'08':20,'09':21,'10':22,'11':23,'12':12}
s = '12:40:22PM'
if s.endswith('AM'):
if s.startswith('12'):
s1=s[:8]
bb=s1.replace('12','00')
print bb
else:
s1=s[:8]
print s1
else:
s1=s[:8]
time= str(s[:2])
ora=str(dicti[time])
aa=s1.replace(time,ora)
print aa
还有一种干净利落的方法
def format_to_24hr(twelve_hour_time):
return datetime.strftime(
datetime.strptime(
twelve_hour_time, '%Y-%m-%d %I:%M:%S %p'
), "%Y-%m-%d %H:%M:%S")不要使用“H”来表示小时，而是使用“I”，如下例所示：
from datetime import *
m2 = 'Dec 14 2018 1:07PM'
m2 = datetime.strptime(m2, '%b %d %Y %I:%M%p')
print(m2)
请检查此链接
''' 检查时间是“AM”还是“PM”以及是否以
12（中午或早上）。如果时间是中午 12 点之后，那么我们添加
12 给它，否则我们就让它保持原样。如果时间是 12
早上有事，我们将 12 转换为 (00) '''
定义时间转换：
if s[-2:] == 'PM' and s[:2] != '12':
time = s.strip('PM')
conv_time = str(int(time[:2])+12)+time[2:]
elif s[-2:] == 'PM' and s[:2] == '12':
conv_time = s.strip('PM')
elif s[-2:] == 'AM' and s[:2] == '12':
time = s.strip('AM')
conv_time = '0'+str(int(time[:2])-12)+time[2:]
else:
conv_time = s.strip('AM')
return conv_time
最基本的方法是：
t_from_str_12h = datetime.datetime.strptime(s, "%I:%M:%S%p")
str_24h = t_from_str.strftime("%H:%M:%S")
#format HH:MM PM
def convert_to_24_h(hour):
if "AM" in hour:
if "12" in hour[:2]:
return "00" + hour[2:-2]
return hour[:-2]
elif "PM" in hour:
if "12" in hour[:2]:
return hour[:-2]
return str(int(hour[:2]) + 12) + hour[2:5]
由于大部分手动计算看起来有点复杂，所以我分享一下我的方法。
# Assumption: Time format (hh:mm am/pm) - You can add seconds as well if you need
def to_24hr(time_in_12hr):
hr_min, am_pm = time_in_12hr.lower().split()
hrs, mins = [int(i) for i in hr_min.split(":")]
hrs %= 12
hrs += 12 if am_pm == 'pm' else 0
return f"{hrs}:{mins}"
print(to_24hr('12:00 AM'))
# 12-hour to 24-hour time format
import re
s = '12:05:45PM'
def timeConversion(s):
hour = s.split(':')
lastString = re.split('(\d+)', hour[2])
if len(hour[2]) > 2:
hour[2] = lastString[1]
if 'AM' not in hour or 'am' not in hour or int(hour[0]) < 12:
if (lastString.__contains__('PM') and int(hour[0]) < 12) or (lastString.__contains__('pm') and int(hour[0]) < 12):
hour[0] = str(int(hour[0]) + 12)
if hour[0] == '12' and (lastString.__contains__('AM') or lastString.count('am')):
hour[0] = '00'
x = "{d}:{m}:{y}".format(d=hour[0], m=hour[1], y=hour[2])
return x
print(timeConversion(s))
这是我的解决方案，使用 python 内置函数将 12 小时时间格式转换为 24 小时时间格式
def time_conversion(s):
if s.endswith('AM') and s.startswith('12'):
s = s.replace('12', '00')
if s.endswith('PM') and not s.startswith('12'):
time_s = s.split(':')
time_s[0] = str(int(time_s[0]) + 12)
s = ":".join(time_s)
s = s.replace('AM', '').replace('PM', '')
return s
time_conversion('07:05:45PM')
19:05:45
碱基分别为 12 和 24。 在这种情况下，AM/PM 充当以 12 为底的数字系统中第二位的值 0 或 1。
| 时间 | 基数 12 | 基数24 |
|---|---|---|
| 凌晨3点 | 03 | 03 |
| 下午3点 | 13 | 0天 |
| 晚上11点 | 1b | 0n |
要从 12 进制转换为 24 进制，以下函数会有所帮助。
def timeConversion(s):
second_order = {
"PM": 1,
"AM": 0
}
hours, rest_time, ampm = s[:2], s[2:-2], s[-2:]
result_hour = second_order[ampm] * 12 + int(hours) % 12
return f'{result_hour:02d}{rest_time}'
%H%Im2 = "1:35" ## This is in the afternoon.
m2 = datetime.strptime(m2, "<b>%I</b>:%M")
print(m2)