如何在不进行昂贵查询的情况下更快地自我联接表（Oracle SQL）

Question

场景

在VER_ID（主键）表中，数据存储在具有不同ATTR_SPEC_ID的多行中。我需要很少的数据，但是我希望它以列格式（请参见屏幕截图），以便可以与其他CTE合并。

而且我不希望查询在生产中花费很多，因为它会花费很多时间。那么处理这种情况的最佳方法是什么？

表格内容

期望的输出

我担心的查询部分

完整查询

SELECT COUNT(CUST_ORD_NO),ORDER_DELIVERY_DATE,SCENARIO
FROM
(WITH 
CFS_ORD AS --- To Filter and get details of Running Retail Order
(  
SELECT CF.ORD_NO,CF.CUST_ORD_NO,CF.RFS_DATE AS ORDER_DELIVERY_DATE
    FROM OM_CFS_ORD CF
    JOIN OPBS_DICT_VALUE OD ON CF.STAGE=OD.VALUE
        WHERE CF.CFS_SPEC_ID ='C16080300451141'  -- SPEC_ID OF EU_ACCESS 
        AND CF.ORD_STATE NOT IN('F','C')    -- To exclude order that has reached end state
        AND OFFER_NAME='Retail Access'
        AND OD.DICT_ID = 'OM_ORD_STAGE'
        AND STATE='A'
        AND CF.RFS_DATE < TRUNC(SYSDATE)
        AND CF.RFS_DATE > TRUNC(SYSDATE-60)
),
CFS_MAIN AS -- To Get VER_ID of EU_ACCESS of the Order
(
SELECT VER_ID,CUST_ORD_NO,SERVICE_NO,CREATE_ORD
    FROM SRV_CFSVER_CT_MAIN
    WHERE VER_STATE='O'
    AND CFS_SPEC_ID ='C16080300451141' -- TO filter EU Access of Retail orders   
),
CFS_ATTR AS (  -- To get necessary attributes
SELECT DISTINCT CFS_ATTRO.VER_ID,
        (SELECT ATTR_VAL FROM SRV_CFS_VER_ATTR WHERE VER_ID=CFS_ATTRO.VER_ID AND ATTR_ID='C16080300451141.APPOINTMENT_ACT_TYPE' ) AS APPOINTMENT_ACTIVITY_TYPE,
        (SELECT ATTR_VAL FROM SRV_CFS_VER_ATTR WHERE VER_ID=CFS_ATTRO.VER_ID AND ATTR_ID='C16080300451141.NL_TYPE' ) AS NL_TYPE,
        (SELECT ATTR_VAL FROM SRV_CFS_VER_ATTR WHERE VER_ID=CFS_ATTRO.VER_ID AND ATTR_ID='C16080300451141.PATCHLESS' ) AS PATCH_LESS,
        (SELECT ATTR_VAL FROM SRV_CFS_VER_ATTR WHERE VER_ID=CFS_ATTRO.VER_ID AND ATTR_ID='C16080300451141.CARRIER_TECH_TYPE' ) AS TECHNOLOGY_TYPE,
        (SELECT ATTR_VAL FROM SRV_CFS_VER_ATTR WHERE VER_ID=CFS_ATTRO.VER_ID AND ATTR_ID='C16080300451141.CARRIER_TYPE' ) AS CARRIER_TYPE
FROM SRV_CFS_VER_ATTR CFS_ATTRO  
     WHERE CFS_ATTRO.ATTR_ID IN ('C16080300451141.PATCHLESS','C16080300451141.NL_TYPE','C16080300451141.APPOINTMENT_ACT_TYPE','C16080300451141.CARRIER_TECH_TYPE')
),
APPOINTMENT AS 
(
SELECT ORD_NO,APPOINTMENT_NO 
    FROM OM_ORD_TIMESLOT
    WHERE STATE='A'
)   
SELECT CFS_ORD.CUST_ORD_NO,CFS_ORD.ORDER_DELIVERY_DATE,
        CASE
            WHEN    CFS_ATTR.APPOINTMENT_ACTIVITY_TYPE IS NULL  AND CFS_ATTR.CARRIER_TYPE <> 'Fiber' THEN 'nDIY'
            WHEN    CFS_ATTR.PATCH_LESS = 'Y' THEN 'PATCHLESS'
            WHEN    CFS_ATTR.APPOINTMENT_ACTIVITY_TYPE IS NOT NULL THEN 'DIY'
            WHEN    APPOINTMENT.APPOINTMENT_NO IS NOT NULL  AND CFS_ATTR.CARRIER_TYPE = 'Fiber' THEN 'DIY'
            WHEN    APPOINTMENT.APPOINTMENT_NO IS NULL  AND CFS_ATTR.CARRIER_TYPE = 'Fiber' THEN 'nDIY'
        END AS SCENARIO
    FROM CFS_ORD
        JOIN CFS_MAIN ON CFS_ORD.ORD_NO=CFS_MAIN.CREATE_ORD
        JOIN CFS_ATTR ON CFS_MAIN.VER_ID=CFS_ATTR.VER_ID
        LEFT JOIN APPOINTMENT ON APPOINTMENT.ORD_NO=CFS_ORD.ORD_NO
        --WHERE CFS_ORD.CUST_ORD_NO LIKE '%@KPN_CM'
        ) 
GROUP BY ORDER_DELIVERY_DATE,SCENARIO
ORDER BY ORDER_DELIVERY_DATE

Answer 1

听起来您需要使用PIVOThttps://www.techonthenet.com/oracle/pivot.php

如果可以使用提供的测试数据填充http://sqlfiddle.com/示例（基于所需的输出），如果遇到困难，我可以帮助您编写查询。