一个python脚本获取谷歌adwords报告,它在我的本地机器上按预期工作,但当部署在AWS Lambda函数中时,我收到以下错误
{
"errorMessage": "[Errno 30] Read-only file system: '/home/sbx_user1051'",
"errorType": "OSError",
"stackTrace": [
[
"/var/task/lambda_function.py",
24,
"lambda_handler",
"report_downloader = client.GetReportDownloader(version='v201809')"
],
[
"/var/task/googleads/adwords.py",
370,
"GetReportDownloader",
"return ReportDownloader(self, version, server)"
],
[
"/var/task/googleads/adwords.py",
1213,
"__init__",
"self.proxy_config, self._namespace, self._adwords_client.cache)"
],
[
"/var/task/googleads/common.py",
819,
"__init__",
"transport = _ZeepProxyTransport(timeout, proxy_config, cache)"
],
[
"/var/task/googleads/common.py",
667,
"__init__",
"cache = zeep.cache.SqliteCache()"
],
[
"/var/task/zeep/cache.py",
77,
"__init__",
"self._db_path = path if path else _get_default_cache_path()"
],
[
"/var/task/zeep/cache.py",
155,
"_get_default_cache_path",
"os.makedirs(path)"
],
[
"/var/lang/lib/python3.6/os.py",
210,
"makedirs",
"makedirs(head, mode, exist_ok)"
],
[
"/var/lang/lib/python3.6/os.py",
210,
"makedirs",
"makedirs(head, mode, exist_ok)"
],
[
"/var/lang/lib/python3.6/os.py",
220,
"makedirs",
"mkdir(name, mode)"
]
]
}
我知道在Lambda中它只能写入位于tem文件夹中的文件,但令我感到困惑的是,在我的脚本中,我根本不写任何文件,这是我脚本的主要结构:
client = adwords.AdWordsClient.LoadFromStorage('tmp/googleads.yaml')
report_downloader = client.GetReportDownloader(version='v201809')
report_query = (adwords.ReportQueryBuilder()
.Select( str)
.From('ACCOUNT_PERFORMANCE_REPORT')
.During('LAST_7_DAYS')
.Build())
results=report_downloader.DownloadReportAsStringWithAwql( report_query, 'TSV', skip_report_header=True, skip_column_header=True, skip_report_summary=True, include_zero_impressions=False)
campaigns=results.splitlines()
请告知如何解决此问题。 env是python 3.6
看起来Adwords正在使用缓存,默认情况下,缓存会进入运行代码的用户的主目录。要解决此问题,请将环境变量XDG_CACHE_HOME
设置为/tmp/.cache
。您可以在Lambda环境变量中设置它。