使Slack API按钮“执行某些操作”

Question

编辑：因为我问了这个问题，所以我创建了一个ngrok URL来在用户按下按钮时接收Slack POST。

但是，每当我按下按钮时，都会显示："POST / HTTP/1.1" 404 -

我正在使用本地Flask URL，下面的代码：

from flask import Flask, request

app = Flask(__name__)


@app.route('/payload', methods=['POST'])
def incoming_slack_message():
    req = request.get_json(Force=True)
    info = request.form['channel_id']
    print(req)
    print(info)
    print('did it work???')
    return 'action successful'


@app.route('/slack/blocks', methods=['POST'])
def incoming_slack_options():
    req = request.get_json(Force=True)
    info = request.form['payload']
    print(req)
    print(info)
    print('Did it work here??')
    return 'ok'


if __name__ == '__main__':
    app.run(port=3000, debug = True)

我已经读到我需要在代码块中包含callback_id，但是每当我得到TypeError: 'NoneType' object is not subscriptable这是我使用的块，而不是callback_id

{
    "type": "section",
    "text": {
        "type": "mrkdwn",
        "text": "Once your machine is selected, click here."
    },
    "accessory": {
        "type": "button",
        "text": {
            "type": "plain_text",
            "text": "Change",
        },
        "value": "click_me_123",
        "action_id": "button"
    }
}

我确定我的烧瓶代码中有问题，因为我对Flask几乎一无所知。我认为我的Slack Block没有什么问题，但是我仍然觉得应该有一个callback_id。感谢您的时间。

Answer 1

好，我已经获得了生成回复的按钮！ Flask代码如下

from flask import Flask, request, Response
import requests
import json

app = Flask(__name__)

@app.route('/', methods=['POST'])
def resp():
    data = request.json
    #if data['event']['type'] == "app_mention":
    #user_text = data['payload']
    #print(data)
    #user = data['event']['user']
    webhook_url = 'Your Webhook URL'
    slack_data = { 'text': "How can I help you ?"}
    response = requests.post(
    webhook_url, data=json.dumps(slack_data),
    headers={'Content-Type': 'application/json'}
    )
    return(response )

if __name__ == '__main__':
    app.run(port=3000, debug = True)

我仍然不知道如何获取数据，＃的零件产生错误，但我会继续寻找。