用于在tfs 2015/2017中对构建进行排队的批处理脚本

问题描述 投票:1回答:2

我试图使用批处理脚本执行构建,我写了一个,但收到此错误:

请定义构建定义名称。 tfsbuild start / collection:https://tfs.prod.dcx.int.bell.ca/tfs/bellca/Consumer/builds/All Definitions / {Release)/ {Project-name} / {Build definition name}

我怎么能解决这个问题?

visual-studio tfs tfs2017
2个回答
1
投票

tfsbuild命令行工具仅适用于XAML构建。对于现代版本,您需要为REST API使用REST API或C#包装器。

文档有很好的例子,但基本上POST https://{instance}/DefaultCollection/{project}/_apis/build/builds?api-version={version}

有适当的身体:

{
  "definition": {
    "id": 25
  },
  "sourceBranch": "refs/heads/master",
  "parameters": "{\"system.debug\":\"true\",\"BuildConfiguration\":\"debug\",\"BuildPlatform\":\"x64\"}"
}

1
投票

是的,正如Daniel所说,您需要使用REST API,请参阅Queue-a-build

您可以简单地使用PowerShell脚本下面对构建进行排队(只需相应地替换params):

Param(
   [string]$collectionurl = "http://server:8080/tfs/DefaultCollection",
   [string]$projectName = "ProjectName",
   [string]$keepForever = "true",
   [string]$BuildDefinitionId = "34",
   [string]$user = "username",
   [string]$token = "password"
)

# Base64-encodes the Personal Access Token (PAT) appropriately
$base64AuthInfo = [Convert]::ToBase64String([Text.Encoding]::ASCII.GetBytes(("{0}:{1}" -f $user,$token)))

function CreateJsonBody
{

    $value = @"
  {
  "definition": {
    "id": $BuildDefinitionId
  },

  "parameters": "{\"system.debug\":\"true\",\"BuildConfiguration\":\"debug\",\"BuildPlatform\":\"x64\"}"
}
"@

 return $value
}

$json = CreateJsonBody

$uri = "$($collectionurl)/$($projectName)/_apis/build/builds?api-version=2.0"
$result = Invoke-RestMethod -Uri $uri -Method Post -Body $json -ContentType "application/json" -Headers @{Authorization=("Basic {0}" -f $base64AuthInfo)}
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