似乎我正在使用原始的迭代器...但是我不知道如何/在哪里。据我所理解的这段代码,Sequence :: map构建了一个新的生成器以在每次调用时进行迭代,因此它应该能够每次都重复使用相同的seq。有人可以帮助我了解我所缺少的吗?
// A wrapper for a generatorFn
class Sequence {
constructor(generatorFn) {
if (typeof generatorFn === "function") {
this[Symbol.iterator] = generatorFn;
} else {
throw new Error("Cannot create Sequence from provided argument");
}
}
static of(obj) {
//Create a generatorFn from an iterable object
function* genFn() {
for (const x of obj) {
yield x;
}
}
return new Sequence(genFn);
}
map(fn) {
//Make a generator from the generator function
const gen = this[Symbol.iterator]();
//Make a new generator function that applies fn to each value
function* mapGenFn() {
for (const x of gen) {
yield fn(x);
}
}
// Create a new sequence using the new generator function
return new Sequence(mapGenFn);
}
reduce(fn, initial) {
let acc;
let first = true;
// Make a new generator from the seq's generator fn
const gen = this[Symbol.iterator]();
if (initial) {
acc = initial
// iterate on the new generator
for (const x of gen) {
acc = fn(acc, x);
}
} else {
acc = this.fold(fn);
}
return acc;
}
fold(fn) {
const gen = this[Symbol.iterator]();
let first = true;
let acc;
for (const x of gen) {
if (first) {
acc = x;
first = false;
} else {
acc = fn(acc, x);
}
}
return acc;
}
}
const seqA = Sequence.of([1,2,3])
console.log("SeqA1 is: ", seqA.reduce((acc, x) => acc + x)); // 6
console.log("SeqA2 is: ", seqA.reduce((acc, x) => acc + x)); // 6
console.log("SeqA3 is: ", seqA.reduce((acc, x) => acc + x)); // 6
const seqB = Sequence.of([1,2,3]).map(x => x + 1);
console.log("SeqB1 is: ", seqB.reduce((acc, x) => acc + x)); // 9
console.log("SeqB2 is: ", seqB.reduce((acc, x) => acc + x)); // undefined
console.log("SeqB3 is: ", seqB.reduce((acc, x) => acc + x)); // undefined
证明问题的小提琴:https://jsfiddle.net/qsh9mupz/5/
当直接减少一个新创建的序列时,我可以多次缩小同一序列,但是如果我尝试重复减少从.map创建的序列,它仅在第一个...起作用吗?] >> < [
const gen = this[Symbol.iterator]()
。.map(…)
时仅创建一次。将该部分移到mapGenFn
中:map(fn) {
const gen = this[Symbol.iterator]; // no call here!
return new Sequence(function* mapGenFn() {
for (const x of gen()) {
// ^^ create new iterator here every time the sequence uses mapGenFn
yield fn(x);
}
});
}