如何使用Apple Silicon获得在MacOS上运行Python解释器的架构？

Question

运行Python通用二进制文件（x86_64、arm64）时，如何从Python内部检查它是否正在运行x86_64或arm64可执行文件？似乎

os.uname()

和

platform.machine()

总是给出实际的系统架构（即“arm64”），而

sysconfig.get_platform()

总是给出“universal2”（也没有帮助）。

那么如何区分 Python 运行为

python3

或

arch -x86_64 python3

的区别？

Answer 1

好吧，我认为以下函数应该报告正确的机器架构（即正在运行的解释器的机器架构，而不是系统的机器架构），也适用于其他操作系统：

def get_platform():
"""Return a string with current platform (system and machine architecture).

This attempts to improve upon `sysconfig.get_platform` by fixing some
issues when running a Python interpreter with a different architecture than
that of the system (e.g. 32bit on 64bit system, or a multiarch build),
which should return the machine architecture of the currently running
interpreter rather than that of the system (which didn't seem to work
properly). The reported machine architectures follow platform-specific
naming conventions (e.g. "x86_64" on Linux, but "x64" on Windows).

Example output strings for common platforms:

    darwin_(ppc|ppc64|i368|x86_64|arm64)
    linux_(i686|x86_64|armv7l|aarch64)
    windows_(x86|x64|arm32|arm64)

"""

system = platform.system().lower()
machine = sysconfig.get_platform().split("-")[-1].lower()
is_64bit = sys.maxsize > 2 ** 32

if system == "darwin": # get machine architecture of multiarch binaries
    if any([x in machine for x in ("fat", "intel", "universal")]):
        machine = platform.machine().lower()

elif system == "linux":  # fix running 32bit interpreter on 64bit system
    if not is_64bit and machine == "x86_64":
        machine = "i686"
    elif not is_64bit and machine == "aarch64":
            machine = "armv7l"

elif system == "windows": # return more precise machine architecture names
    if machine == "amd64":
        machine = "x64"
    elif machine == "win32":
        if is_64bit:
            machine = platform.machine().lower()
        else:
            machine = "x86"

# some more fixes based on examples in https://en.wikipedia.org/wiki/Uname
if not is_64bit and machine in ("x86_64", "amd64"):
    if any([x in system for x in ("cygwin", "mingw", "msys")]):
        machine = "i686"
    else:
        machine = "i386"

return f"{system}_{machine}"

不幸的是，我无法使用 M1 Mac 来仔细检查。如果有人可以确认这有效，那就太好了。

Answer 2

我可以通过运行这个来得到它：

python -c "import platform; print(platform.processor())"

输出如下：

在 M1/M2 Mac 上 -->

arm

在较旧的 Mac 上 -->

i386