使tkinter功能不在下一个窗口中显示

Question

我有一个带登录功能的tkinter窗口，允许三个人中的一个登录机场登录系统，“HQ”，“Pilot / Crew”或“customer”。

到目前为止，我可以使用户，我可以使用正在使用的sql登录。

问题是我不知道如何将Dropbox转换为小部件，因此它不会在下一个窗口中消失。

    # imports
from tkinter import *
import tkinter as tk
from tkinter import messagebox as ms
import sqlite3

# make database and users (if not exists already) table at programme start up
with sqlite3.connect('quit.db') as db:
    c = db.cursor()

c.execute('CREATE TABLE IF NOT EXISTS user (var TEXT NOT NULL, username TEXT NOT NULL ,password TEXT NOT NULL);')
db.commit()
db.close()

# main Class


class main:
    def __init__(self, master):
        #  Window
        self.master = master
        # Some Usefull variables
        self.var = tk.StringVar()
        self.username = StringVar()
        self.password = StringVar()
        self.n_username = StringVar()
        self.n_password = StringVar()
        # Create Widgets
        self.widgets()

    # def pack():
    #     if self.var.get() = "HQ"

    # Login Function
    def login(self):
        # Establish Connection
        with sqlite3.connect('quit.db') as db:
            c = db.cursor()

        # Find user If there is any take proper action
        find_user = ('SELECT * FROM user WHERE var = ? and username = ? and password = ?')
        c.execute(find_user, [(self.var.get()), (self.username.get()), (self.password.get())])
        result = c.fetchall()
        if result:
            self.logf.pack_forget()

            self.head['text'] = self.username.get() + '\n Loged In'
            self.head['pady'] = 150

        else:
            ms.showerror('Oops!', 'something is not right.')


    def new_user(self):
        # Establish Connection
        with sqlite3.connect('quit.db') as db:
            c = db.cursor()

        # Find Existing username if any take proper action
        find_user = ('SELECT * FROM user WHERE username = ?')
        c.execute(find_user, [(self.username.get())])
        if c.fetchall():
            ms.showerror('Error!', 'Username Taken Try a Diffrent One.')
        else:
            ms.showinfo('Success!', 'Account Created!')
            self.log()
        # Create New Account
        insert = 'INSERT INTO user(var,username,password) VALUES(?,?,?)'
        c.execute(insert, [(self.var.get()), (self.n_username.get()), (self.n_password.get())])
        db.commit()

    def dropbox(self):
        OPTIONS = [
            "Please Select",
            "HQ",
            "Pilot/Crew",
            "Customer"
        ]
        self.var.set(OPTIONS[0])
        dropdownmenu = OptionMenu(root, self.var, OPTIONS[0], OPTIONS[1], OPTIONS[2], OPTIONS[3])
        dropdownmenu.pack()


        # Frame Packing Methords
    def log(self):

        self.username.set('')
        self.password.set('')
        self.crf.pack_forget()
        self.head['text'] = 'LOGIN'
        self.logf.pack()

    def cr(self):
        self.n_username.set('')
        self.n_password.set('')
        self.logf.pack_forget()
        self.head['text'] = 'Create Account'
        self.crf.pack()

    # Draw Widgets
    def widgets(self):
        self.head = Label(self.master, text='LOGIN', font=('', 35), pady=10)
        self.head.pack()
        self.logf = Frame(self.master, padx=10, pady=10)
        self.dropbox()
        Label(self.logf, text='Username: ', font=('', 20), pady=5, padx=5).grid(row=2, column=0)
        Entry(self.logf, textvariable=self.username, bd=5, font=('', 15)).grid(row=2, column=1)
        Label(self.logf, text='Password: ', font=('', 20), pady=5, padx=5).grid(sticky=W)
        Entry(self.logf, textvariable=self.password, bd=5, font=('', 15), show='*').grid(row=3, column=1)
        Button(self.logf, text='Login', bd=3, font=('', 15), padx=5, pady=5, command=self.login).grid()
        Button(self.logf, text='Create Account', bd=3, font=('', 15), padx=5, pady=5, command=self.cr).grid(row=4, column=1)
        self.logf.pack()

        self.crf = Frame(self.master, padx=10, pady=10)
        Label(self.crf, text='Select:', font=('', 20), pady=5, padx=5).grid(row=1, column=0)
        Label(self.crf, text='Username: ', font=('', 20), pady=5, padx=5).grid(sticky=W)
        Entry(self.crf, textvariable=self.n_username, bd=5, font=('', 15)).grid(row=2, column=1)
        Label(self.crf, text='Password: ', font=('', 20), pady=5, padx=5).grid(sticky=W)
        Entry(self.crf, textvariable=self.n_password, bd=5, font=('', 15), show='*').grid(row=3, column=1)
        Button(self.crf, text='Create Account', bd=3, font=('', 15), padx=5, pady=5, command=self.new_user).grid()
        Button(self.crf, text='Go to Login', bd=3, font=('', 15), padx=5, pady=5, command=self.log).grid(row=4, column=1)


# create window and application object
root = tk.Tk()
# root.title("Login Form")
main(root)
root.mainloop()

这是我目前的代码，它的工作原理。

也有人知道如何将Dropbox从.pack（）更改为.grid（），因为我想找到它我放弃了但它仍然让我烦恼

Answer 1

您可以修改dropbox()以再添加一个参数：parent，并返回创建的OptionMenu（使用parent参数作为其父级而不是root），如下所示：

def dropbox(self, parent):
    OPTIONS = [
        "Please Select",
        "HQ",
        "Pilot/Crew",
        "Customer"
    ]
    self.var.set(OPTIONS[0])
    return OptionMenu(parent, self.var, *OPTIONS)

我删除了.pack()的执行，以便您可以使用以后想要的任何布局管理器。

然后修改widgets()如下：

def widgets(self):
    self.head = Label(self.master, text='LOGIN', font=('', 35), pady=10)
    self.head.pack()
    self.logf = Frame(self.master, padx=10, pady=10)
    self.dropbox(self.logf).grid(row=1, column=0, columnspan=2, pady=10)
    Label(self.logf, text='Username: ', font=('', 20), pady=5, padx=5).grid(row=2, column=0)
    Entry(self.logf, textvariable=self.username, bd=5, font=('', 15)).grid(row=2, column=1)
    Label(self.logf, text='Password: ', font=('', 20), pady=5, padx=5).grid(sticky=W)
    Entry(self.logf, textvariable=self.password, bd=5, font=('', 15), show='*').grid(row=3, column=1)
    Button(self.logf, text='Login', bd=3, font=('', 15), padx=5, pady=5, command=self.login).grid()
    Button(self.logf, text='Create Account', bd=3, font=('', 15), padx=5, pady=5, command=self.cr).grid(row=4, column=1)
    self.logf.pack()

    self.crf = Frame(self.master, padx=10, pady=10)
    Label(self.crf, text='Select:', font=('', 20), pady=5, padx=5).grid(row=1, column=0)
    self.dropbox(self.crf).grid(row=1, column=1, sticky=W)
    Label(self.crf, text='Username: ', font=('', 20), pady=5, padx=5).grid(sticky=W)
    Entry(self.crf, textvariable=self.n_username, bd=5, font=('', 15)).grid(row=2, column=1)
    Label(self.crf, text='Password: ', font=('', 20), pady=5, padx=5).grid(sticky=W)
    Entry(self.crf, textvariable=self.n_password, bd=5, font=('', 15), show='*').grid(row=3, column=1)
    Button(self.crf, text='Create Account', bd=3, font=('', 15), padx=5, pady=5, command=self.new_user).grid()
    Button(self.crf, text='Go to Login', bd=3, font=('', 15), padx=5, pady=5, command=self.log).grid(row=4, column=1)

另外我认为代码中下面块的缩进是错误的：

with sqlite3.connect('quit.db') as db:
    c = db.cursor()
# wrong indentation?
c.execute('CREATE TABLE IF NOT EXISTS user (var TEXT NOT NULL, username TEXT NOT NULL ,password TEXT NOT NULL);')
db.commit()
db.close()

它应该是：

with sqlite3.connect('quit.db') as db:
    c = db.cursor()
    c.execute('CREATE TABLE IF NOT EXISTS user (var TEXT NOT NULL, username TEXT NOT NULL ,password TEXT NOT NULL);')
    db.commit()
    # no need to call db.close() as the db will be closed when exiting the with block

类似的问题适用于您的代码中稍后的其他with sqlite3.connect(...) as db语句。