要插入countif的SQL语法

Question

我有一张桌子（tbl2）i have 4 columns with feedback attributes listed。我需要生成一个数据透视表，如mysql中的语法。需要类似pivot table的输出。我目前正在尝试

INSERT INTO 1 (`BAD/GOOD`, `PRICE YES`, `PRICE NO`, `TOTAL PRICE`) SELECT "BAD",COUNT(*) WHERE tbl2.PRICE="BAD" AND tbl2.Churn="YES",COUNT(*) WHERE tbl2.PRICE="BAD" AND tbl2.Churn="NO",COUNT(*) WHERE tbl2.PRICE="BAD" FROM tbl2_customers_churn

并且还尝试将其插入为值

INSERT INTO 1 VALUES ("BAD",COUNT(*) FROM tbl2 WHERE tbl2.PRICE="BAD" AND tbl2.Churn="YES",COUNT(*) FROM tbl2 WHERE tbl2.PRICE="BAD" AND tbl2.Churn="NO",COUNT(*) FROM tbl2 WHERE tbl2.PRICE="BAD")

分别针对坏账和好账

有人建议如何在SQL中解决此问题吗？

Answer 1

我认为您想要这样的逻辑：

INSERT INTO 1 (`BAD/GOOD`, `PRICE YES`, `PRICE NO`, `TOTAL PRICE`)
    SELECT 'BAD',
            SUM(CASE WHEN tbl2.PRICE = 'BAD' AND tbl2.Churn = 'YES' THEN 1 ELSE 0 END),
            SUM(CASE WHEN tbl2.PRICE = 'BAD' AND tbl2.Churn = 'NO' THEN 1 ELSE 0 END),
            SUM(CASE WHEN tbl2.PRICE = 'BAD' THEN 1 ELSE 0 END)
    FROM tbl2_customers_churn tbl2;

或更简单：

    SELECT 'BAD',
            SUM(CASE WHEN tbl2.Churn = 'YES' THEN 1 ELSE 0 END),
            SUM(CASE WHEN tbl2.Churn = 'NO' THEN 1 ELSE 0 END),
            COUNT(*)
    FROM tbl2_customers_churn tbl2
    WHERE tbl2.PRICE = 'BAD'