复制列而不进行覆盖

问题描述 投票:0回答:1

我有3个不同的Excel工作表,分别称为:wsOrigin1,wsOrigin2,wDestiny。我使用此代码来定位和复制wsDestiny中wsOrigin1和wsOrigin2的整个列,该列位于wsOrigin1和wsOrigin2的第一行,即“此处”的列,然后将wsOrigin1列复制到wsDestiny工作表中找到wsOrigin2的列下,但是我遇到的问题是我这样做的代码,这是在编写复制了wsOrigin2的列之后进行的,而我首先复制了wsOrigin1。这是我使用的代码:

  For c = 1 To 13
      If wsOrigin1.Cells(1, c).Value = "here" Then
         For cc = cc + 1 To 13
         ' fila , columna

            With wsOrigin1.Columns(c).CurrentRegion
          wsDestiny.Columns(cc).End(xlDown) _
          .Offset(1, 0).Resize(.Rows.Count).End(xlDown) = .Columns(c).Value
       End With

          Exit For
          Next cc
     End If
   Next c


   For c2 = 1 To 13
      If wsOrigin2.Cells(1, c2).Value = "here" Then
         For cc2 = cc2 + 1 To 13
         ' fila , columna

            With wsOrigin2.Columns(c2).CurrentRegion
         wsDestiny.Columns(cc2).End(xlUp) _
          .Offset(1, 0).Resize(.Rows.Count) = .Columns(c2).End(xlUp).Value
       End With

          Exit For
          Next cc2
     End If
   Next c2
excel vba
1个回答
0
投票
For c = 1 To 13
      If wsOrigin1.Cells(1, c).Value = "here" Then
         For cc = cc + 1 To 13

           With wsOrigin1.Columns(c).CurrentRegion
           wsDestiny.Cells(Rows.Count, cc).End(xlUp) _
           .Offset(1, 0).Resize(.Rows.Count) = .Columns(c).Value
           End With

           Exit For
          Next cc
     End If
   Next c


For c2 = 1 To 13
     If wsOrigin2.Cells(1, c2).Value = "here" Then
      For cc2 = cc2 + 1 To 13

       With wsOrigin2.Columns(c2).CurrentRegion
         wsDestiny.Cells(Rows.Count, cc2).End(xlUp) _
          .Offset(1, 0).Resize(.Rows.Count) = .Columns(c2).Value
         End With

         Exit For
        Next cc2
   End If
 Next c2   

示例结果:

wsOrigin1:

   A    B    C  
1 here      here   
2 bla  ble  bli
3 bla  ble  bli
4 bla  ble  bli

wsOrgin2:

   A
1 here
2 blo
3 blo
4 blo

Result
code compile

wsDestiny:

   A    B      
1 here here   
2 bla  bli
3 bla  bli
4 bla  bli
5 here
6 blo
7 blo
8 blo
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