对列表中的单词进行计数，并将它们以及出现的次数与Python一起添加到字典中

Question

为了清楚起见，我在下面输入我的代码要回答的问题，但是我遇到了2个问题。似乎正确地加了一点，句子中其他单词的计数结果似乎是准确的，但是兔子突然从1跳到4，我不确定为什么。

我也得到这个：错误：AttributeError：'int'对象没有属性'items'

这是我的代码后面的问题。谢谢！

提供的是保存在变量名句子中的字符串。将字符串拆分为单词列表，然后创建一个包含每个单词及其出现次数的字典。将此字典保存到变量名word_counts。

sentence = "The dog chased the rabbit into the forest but the rabbit was too quick."
sentence_case = sentence.lower()
sentence_list = sentence_case.split()
sentence_dictionary = {}
word_counts = 0

for item in sentence_list:
    if item in sentence_dictionary:
        word_counts += 1
        sentence_dictionary[item] = word_counts

    else:
        sentence_dictionary[item] = 1

Answer 1

尝试一下

sentence = "The dog chased the rabbit into the forest but the rabbit was too quick."
sentence_case = sentence.lower()
sentence_list = sentence_case.split()
sentence_dictionary = {}

for item in sentence_list:
    if item in sentence_dictionary:
        sentence_dictionary[item] += 1

    else:
        sentence_dictionary[item] = 1

Answer 2

如果我理解的正确，您可以删除word_count变量以计算单词的出现频率

sentence = "The dog chased the rabbit into the forest but the rabbit was too quick."
sentence_case = sentence.lower()
sentence_list = sentence_case.split()
sentence_dictionary = {}

for item in sentence_list:
    if item in sentence_dictionary:
        sentence_dictionary[item] += 1

    else:
        sentence_dictionary[item] = 1

print(sentence_dictionary)

如果要保存在word_counts中，可以这样设置：

word_counts = sentence_dictionary

希望我能为您提供帮助