类型错误：Updater.__init__() 得到了意外的关键字参数“token”

Question

我有这段代码，应该在电报中查找 /help 命令。因此，一旦您在电报频道中输入 /help，它就会为您提供选项。代码如下。

from telegram import Update
from telegram.ext import Updater, CommandHandler, MessageHandler, CallbackContext
from telegram.ext import filters

# Define your bot token here
TOKEN = "YOUR_BOT_TOKEN"


def start(update, context):
    update.message.reply_text("Welcome to your Telegram bot!")

def help_command(update, context):
    update.message.reply_text("You requested help. Here are some available commands:\n"
                              "/help - Show this help message\n"
                              "/start - Start the bot")

def handle_message(update, context):
    text = update.message.text
    if text == '/start':
        start(update, context)
    elif text == '/help':
        help_command(update, context)

def main():
    # Initialize the Updater with your bot token
    updater = Updater(token=TOKEN, use_context=True)
    dispatcher = updater.dispatcher

    # Define the command handlers
    dispatcher.add_handler(CommandHandler("start", start))
    dispatcher.add_handler(CommandHandler("help", help_command))

    # Handle non-command messages using a filter
    dispatcher.add_handler(MessageHandler(Filters.text & ~Filters.command, handle_message))

    # Start the bot
    updater.start_polling()
    updater.idle()

if __name__ == '__main__':
    main()

但是我收到此错误

TypeError: Updater.__init__() got an unexpected keyword argument 'token'

您能否告诉我如何解决此错误。

Answer 1

Updater类有两个参数，

bot

和

update_queue

。您需要首先创建一个 telegram.Bot 实例和 asyncio.Queue 实例：

from asyncio import Queue
from telegram import Bot
from telegram.ext import Updater

bot = Bot(TOKEN, ...)
update_queue = Queue()

updater = Updater(bot, update_queue)

我对

Telegram

一点也不熟悉，对

asyncio

的了解也有限，所以这是我能提供的最大帮助。