Javascript：在深度嵌套的数组和对象中查找匹配的属性值

Question

我需要匹配来自两个 JSON 源的值。当“城市”数组的嵌套更浅一层

（只是一组对象）

时，以这种方式使用javascriptfind方法对我有用，但它不适用于更深的嵌套（其中的一组对象一组对象）.

本质上，我想做的是循环遍历

feeds[0].feed.details.place

数组并为每个数组找到匹配的

cities.CountyPlaces.PlaceFIPSCode

值。

// console.log(feeds[0].feed.details.place);
// console.log(cities[1].CountyPlaces[2].PlaceName);
feeds[0].feed.details.place.map(async (arrItem, z) => {
  console.log('arrItem: ', arrItem);
  const cityMatch = await cities.find((cityObject, i) => {
    // console.log(i, 'cityObject: ', cityObject);
    arrItem === cityObject.PlaceName;
  });
  if (cityMatch !== undefined) {
    // --> THIS IS WHERE I NEED TO MANIPULATE MATCHING DATA
    console.log(
      z,
      'cityMatch: ',
      arrItem,
      cityMatch.PlaceName,
      cityMatch.PlaceFIPSCode
    );
  } else {
    // there should be a defined match for every "place" and no else results
    console.log(z, '💥 cityMatch UNDEFINED', arrItem);
  }
});

这是我使用的数据示例，具有相同的嵌套：

const feeds = [
  {
    feed: {
      record: '0002',
      details: {
        county: ['Alameda'],
        place: ['Alameda', 'Berkeley', 'Oakland'],
      },
    },
  },
];
const cities = [
  {
    CountyName: 'San Francisco',
    CountyFIPSCode: '075',
    CountyPlaces: [
      {
        PlaceName: 'San Francisco',
        PlaceFIPSCode: '67000',
      },
    ],
  },
  {
    CountyName: 'Alameda',
    CountyFIPSCode: '001',
    CountyPlaces: [
      {
        PlaceName: 'Alameda',
        PlaceFIPSCode: '00562',
      },
      {
        PlaceName: 'Albany',
        PlaceFIPSCode: '00674',
      },
      {
        PlaceName: 'Berkeley',
        PlaceFIPSCode: '06000',
      },
      {
        PlaceName: 'Emeryville',
        PlaceFIPSCode: '22594',
      },
      {
        PlaceName: 'Oakland',
        PlaceFIPSCode: '53000',
      },
    ],
  },
];

Answer 1

您可以根据

cities

匹配

CountyName

过滤

details.county[0]

数组，然后根据

CountyPlaces

在

PlaceName

中过滤匹配城市的

details.place

：

const feeds = [
  {
    feed: {
      record: '0002',
      details: {
        county: ['Alameda'],
        place: ['Alameda', 'Berkeley', 'Oakland'],
      },
    },
  },
];

const cities = [
  {
    CountyName: 'San Francisco',
    CountyFIPSCode: '075',
    CountyPlaces: [
      {
        PlaceName: 'San Francisco', PlaceFIPSCode: '67000',
      },
    ],
  },
  {
    CountyName: 'Alameda',
    CountyFIPSCode: '001',
    CountyPlaces: [
      {
        PlaceName: 'Alameda', PlaceFIPSCode: '00562',
      },
      {
        PlaceName: 'Albany', PlaceFIPSCode: '00674',
      },
      {
        PlaceName: 'Berkeley', PlaceFIPSCode: '06000',
      },
      {
        PlaceName: 'Emeryville', PlaceFIPSCode: '22594',
      },
      {
        PlaceName: 'Oakland', PlaceFIPSCode: '53000',
      },
    ],
  },
];

const county = feeds[0].feed.details.county[0];
const places = feeds[0].feed.details.place;

const result = cities
  .filter(city => city.CountyName == county)[0]
  .CountyPlaces.filter(({ PlaceName }) => places.includes(PlaceName))
  
console.log(result)

Answer 2

如果我明白你的问题，你能试试下面的代码吗？

const cityMatch = await cities.find((cityObject, i) => {
    // console.log(i, 'cityObject: ', cityObject);
    cityObject.CountyPlaces.some(p=>p.PlaceName===arrItem)
   
  });