(php)我在“get”方法链接中获得了额外的代码

问题描述 投票:0回答:2

我的第一个问题溢出:)

我试图创建一个表来显示SQL的所有帖子。我已经完成了下一个代码:

function show_all_posts_in_table(){
        global $connection;
        $query = "SELECT * FROM posts";
        $all_posts_content_query = mysqli_query($connection,$query);

        while ($row = mysqli_fetch_assoc($all_posts_content_query)) {
            $post_id_display = $row['post_id'];
            echo "<tr>";
            echo "<td>" . $post_id_display = $row['post_id'] . "</td>";
            echo "<td>" . $post_category_display = $row['post_category_id'] . "</td>";
            echo "<td>" . $post_title_display = $row['post_title'] . "</td>";
            echo "<td>" . $post_author_display = $row['post_author'] . "</td>";
            echo "<td>" . $post_date_display = $row['post_date'] . "</td>";
            $post_image_display = $row['post_image'];
            echo "<td>" . "<img src= '../images/{$post_image_display}' width='200' height='auto'>" . "</td>";
            echo "<td>" . $post_content_display = $row['post_content'] . "</td>";
            echo "<td>" . $post_tags_display = $row['post_tags'] . "</td>";
            echo "<td>" . $post_status_display = $row['post_status'] . "</td>";
            echo "<td>{$post_id_display}</td>";
            echo "<td> <a href='posts.php?delete={$post_id_display}'>DELETE</a> </td>";
            echo "</tr>";
}
}

我看到我制作的桌子上的所有帖子,一切正常。

问题是当我尝试删除其中一个帖子时(用“get”方法删除href)。

出于某种原因,我无法理解,在chrome的地址行上我得到了额外的</td>

我被引导到:posts.php?delete=6</td>

任何人都能理解为什么会这样吗?

谢谢!

php sql methods get slug
2个回答
0
投票

$post_id_display = $row['post_id'] . "</td>";$post_id_display设置为$row['post_id'],然后将</td>连接到它。

无需将这些值存储在单独的变量中。只需直接使用$row数组即可。

将其更改为:

while ($row = mysqli_fetch_assoc($all_posts_content_query)) {
    echo "<tr>";
    echo "<td>" . $row['post_id'] . "</td>";
    echo "<td>" . $row['post_category_id'] . "</td>";
    echo "<td>" . $row['post_title'] . "</td>";
    echo "<td>" . $row['post_author'] . "</td>";
    echo "<td>" . $row['post_date'] . "</td>";
    echo "<td>" . "<img src= '../images/" . $row['post_image'] . "' width='200' height='auto'>" . "</td>";
    echo "<td>" . $row['post_content'] . "</td>";
    echo "<td>" . $row['post_tags'] . "</td>";
    echo "<td>" . $row['post_status'] . "</td>";
    echo "<td>" . $row['post_id'] . "</td>";
    echo "<td> <a href='posts.php?delete=" . $row['post_id'] . "'>DELETE</a> </td>";
    echo "</tr>";

......它应该有效。


0
投票

作为@MagnusEriksson的答案的扩展只是对正在发生的事情的一点测试/简化:

你现在做了什么:

$a = "A";
$b = "B";
echo "x" . $a = $b . "y"; // -> xBy
echo " value of A: ".$a; // -> value of A: By

这可行:

$a = "A";
$b = "B";
echo "x" . ($a = $b) . "y"; // -> xBy
echo " value of A: ".$a;  // -> value of A: B
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