csv的带雇员编号的csv中的SamAccountName

Question

我有这个工作脚本：

    Import-CSV -Path "$home\desktop\Script\fi13.04.20.csv" | ForEach-Object {

    Get-ADUser -Filter "employeeid -like '*$($_.employeeid)*'"  -Properties employeeid | select employeeid,name,SamAccountName

} | Export-CSV "$home\desktop\Script\fi-san-out.csv" -Encoding UTF8 -NoTypeInformation

我给他一个带员工编号的CSV文件，并向后发送一个带有SamAccountName的文件...带有特定参数的雇员ID和雇员ID。

这是一个改进的版本-

$csv = Import-CSV -Path "$home\desktop\Script\fi13.04.20.csv"

$csvOutput = "$home\desktop\Script\fi-san-out.csv"

$object = @()

foreach($employee in $csv){

    $ADUserObject = Get-ADUser -Filter "employeeID -eq '$($employee.employeeID)'" -Properties samAccountName, displayName ,employeeID  -ErrorAction SilentlyContinue

    if($ADUserObject){

        $object += New-Object psobject -Property @{

            displayName = $ADUserObject.displayName

            samAccountName = $ADUserObject.SamAccountName

            employeeID = $ADUserObject.employeeID

        }

    }else{

        Write-Host "No employee found for $($employee.employeeId)" -ForegroundColor Red

    }

}

if($object){

    $object | Select-Object displayName, samAccountName, employeeID | Export-Csv -Path $csvOutput -Delimiter "," -Encoding UTF8 -NoTypeInformation

}

第一个版本会产生更多结果，因为如果employeeID包含错误“例如，CSV 12345中的employeeID和ActiveDirectory 123456中的employeeID”，它将给出结果。在改进的版本中，它会使用任何不正确的ID引发错误。问题是如何更改改进的版本，以便即使出现错误也能产生结果（如示例中所示）？我才刚刚开始学习PS，并在帮助下编写了改进的版本。

Answer 1

结果

$csv = Import-CSV -Path "$home\desktop\Script\ID.csv"

$csvOutput = "$home\desktop\Script\tz-san-out.csv"

$object = @()

foreach($employee in $csv){

    $ADUserObject = Get-ADUser -Filter "employeeID -like '*$($employee.employeeID)*'" -Properties samAccountName, displayName ,employeeID  -ErrorAction SilentlyContinue

    if($ADUserObject){

        $object += New-Object psobject -Property @{

            displayName = $ADUserObject.displayName

            samAccountName = $ADUserObject.SamAccountName

            employeeID = $ADUserObject.employeeID

        }

    }else{

        Write-Host "No employee found for $($employee.employeeId)" -ForegroundColor Red

    }

}

if($object){

    $object | Select-Object displayName, samAccountName, employeeID | Export-Csv -Path $csvOutput -Delimiter "," -Encoding UTF8 -NoTypeInformation

}