单选按钮选中香草js时显示div

Question

这里有点挣扎。我的事件侦听器仅检测到单选按钮的“已选中”更改，而不是“未选中”更改。注意：仅纯 javascript (vanillajs)，无 jQuery。

用一点 JSFiddle 来解释我的问题：https://jsfiddle.net/kLuba37w/1/

<label class="checkbox checkbox--block">
    <input type="radio" name="radio" class="" data-show-more data-target="showmoretarget2" value="1"> <span></span> This is the first radio
</label>
<label class="checkbox checkbox--block">
    <input type="radio" name="radio" class="" value="2"> <span></span> This is the second radio
</label>

<div class="js-show-more" data-hook="showmoretarget2">
    <h2 class="h2"> Some more content</h2>
    <p>Lorem ipsum dolor sit amet, consectetur adipisicing elit. Blanditiis ipsum repellendus, officia dolores consectetur. Error at officiis sequi iure earum.</p>
</div>

JS：

(function() {
 "use strict";

  var elements = document.querySelectorAll('[data-show-more]');

  [].forEach.call(elements, function(element) {

      element.addEventListener('change', function(e) {
        e.preventDefault();

        var target = document.querySelectorAll('[data-hook="' + this.getAttribute('data-target') + '"]')[0];
        alert("change detected");


  }, false);

  });

 })();

Answer 1

执行此操作的简单方法是监听选中的事件和名称为 radio 的所有单选按钮

(function() {
  "use strict";

    document.querySelector("#radio1").addEventListener("change", function() {
        alert("checked radio 1");
    });

    document.querySelector("#radio2").addEventListener("change", function() {
        alert("checked radio 2");
    });

})();

Answer 2

document.getElementsByName('radio-button').forEach(function(element) {
  element.onclick = function() {
    alert("change detected");
  }
});

<fieldset>
  <div>
    <input type="radio" name="radio-button" id="button1" value="1" checked>
    <label for="button1">This is the first radio</label>
  </div>
  <div>
    <input type="radio" name="radio-button" id="button2" value="2">
    <label for="button2">This is the second radio</label>
  </div>
</fieldset>