zlib函数找不到符号

问题描述 投票:0回答:1

从标题开始,在编译时

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <sys/types.h>
#include <dirent.h>
#include <unistd.h>
#include <errno.h>
#include <sys/types.h>
#include <dirent.h>
#include <errno.h>
#include <math.h>
#include <pthread.h>
#include <assert.h>
#include <zlib.h>

int main(){

    char *infilename = "triples.txt.gz";
    char *outfilename = "out_test.txt";
    gzFile infile = gzopen(infilename, "rb");
    FILE *outfile = fopen(outfilename, "wb");
    if (!infile || !outfile) return -1;

    char buffer[128];
    int num_read = 0;
    num_read = gzread(infile, buffer, sizeof(buffer)); 
    while (num_read > 0) {
        fwrite(buffer, 1, num_read, outfile);
    }

    gzclose(infile);
    fclose(outfile);
    return 0;
}

我收到消息

Undefined symbols for architecture x86_64:
  "_gzclose", referenced from:
      _main in ccfPmLqz.o
  "_gzopen", referenced from:
      _main in ccfPmLqz.o
  "_gzread", referenced from:
      _main in ccfPmLqz.o
ld: symbol(s) not found for architecture x86_64
collect2: error: ld returned 1 exit status

我在弄清楚它在说些什么时遇到了麻烦。 zlib似乎是在修改代码时安装的,我对某些特定的zlib函数有一些错误(例如gzopen的参数不足)。

c symbols zlib
1个回答
1
投票

编译时未链接zlib。假设zlib在标准路径中,则需要编译为

gcc -lz -o c_test sometest.c
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