__construct期待一个参数,没有传入(Fixtures)

问题描述 投票:0回答:1

我正在为我的项目创建somme fixtures(symfony 3.4),一切似乎都正确,找不到问题,我想念什么?如果有人有想法会很棒:)

use AppBundle\Entity\User;

use AppBundle\Entity\Task;

use Doctrine\Bundle\FixturesBundle\Fixture;

use Doctrine\Common\Persistence\ObjectManager;

use Symfony\Component\Security\Core\Encoder\UserPasswordEncoderInterface;

class AppFixtures extends Fixture
{
private $encoder;

public function __construct(UserPasswordEncoderInterface $encoder)
{
    $this->encoder = $encoder;
}

/**
 * @param ObjectManager $manager
 */
public function load(ObjectManager $manager)
{
    // Create user with role ROLE_ADMIN

    $user_admin = new User();

    $user_admin->setUsername( 'admin' );

    $user_admin->setPassword($this->encoder->encodePassword($user_admin, 'password' ));

    $user_admin->setEmail( '[email protected]' );

    $user_admin->setRoles( 'ROLE_ADMIN' );

    $manager->persist( $user_admin );
symfony fixtures
1个回答
0
投票

您应该实现ContainerAwareInterface并从容器中获取编码器,请参阅此处的答案:How to inject service into Symfony 2 Data Fixtures?

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