AWS lambda中的Alexa自定义技能无法识别Alexa.getSupportedInterfaces [错误处理：Alexa.getSupportedInterfaces不是函数]

Question

[尝试在AWS托管的自定义Lambda函数中使用Alexa演示语言功能。意图处理程序正在触发，但是当我添加Alexa.getSupportedInterfaces失败。消息为“错误处理：Alexa.getSupportedInterfaces不是函数”

// 1. Intent Handlers =============================================
const LaunchRequest_Handler =  {
    canHandle(handlerInput) {
        const request = handlerInput.requestEnvelope.request;
        return request.type === 'LaunchRequest';
    },
    handle(handlerInput) {
       let responseBuilder = handlerInput.responseBuilder;


        let speakOutput = 'Welcome to test Bot. ';
      //  let skillTitle = capitalize(invocationName);

      // Add APL directive to response

        if (Alexa1.getSupportedInterfaces(handlerInput.requestEnvelope)['Alexa.Presentation.APL']) {

            // Add the RenderDocument directive to the responseBuilder
            responseBuilder.addDirective({
                type: 'Alexa.Presentation.APL.RenderDocument',
                token: Echo_Token,
                document: Customer
            });

            // Tailor the speech for a device with a screen.
            speakOutput += " You should now also see my greeting on the screen."
        } else {
            // User's device does not support APL, so tailor the speech to this situation
            speakOutput += " This example would be more interesting on a device with a screen, such as an Echo Show or Fire TV.";
        }
  return responseBuilder
            .speak(speakOutput)
            .withShouldEndSession(false)
            .reprompt('try again, ' + speakOutput)
             .withSimpleCard("CustomerSupport!", "CustomerSupport)")
           // .reprompt('add a reprompt if you want to keep the session open for the user to respond')
            //.withStandardCard('Welcome!', 
             // 'Hello!\nThis is a card for your skill, ' + skillTitle,
             //  welcomeCardImg.smallImageUrl, welcomeCardImg.largeImageUrl)
            .getResponse();
    },
};

Answer 1

而不是使用以下条件：Alexa1.getSupportedInterfaces（handlerInput.requestEnvelope ['Alexa.Presentation.APL]

您可以使用以下条件检查设备是否支持APL：if（supportsAPL（handlerInput））

确保在索引文件中包含以下函数定义：

功能supportsAPL（handlerInput）{常量supportedInterfaces = handlerInput.requestEnvelope.context.System.device.supportedInterfaces; const aplInterface = supportedInterfaces ['Alexa.Presentation.APL'];返回aplInterface！= null && aplInterface！= undefined; }

功能supportsAPLT（handlerInput）{常量supportedInterfaces = handlerInput.requestEnvelope.context.System.device.supportedInterfaces; const aplInterface = supportedInterfaces ['Alexa.Presentation.APLT'];返回aplInterface！= null && aplInterface！= undefined; }

希望它对我的工作有所帮助。