没有用户活动时自动注销

Question

我想在网页中实现自动注销功能，当网页上没有活动时，它将显示登录页面预定的时间间隔（例如15分钟，30分钟，45分钟和60分钟）。我编写了一个侦听特定事件并重置计数器的函数。如果计数器超过，那么我将调用登录页面。

这里的问题是，在用户事件上调用setInterval会进行如此多的函数调用。让我知道，如何避免这种情况。或者，是否有任何其他解决方案来实现这一目标。

var inActiveTimeout = 5; //temp
var minInActiveTimeout = 5;
var idleTime = minInActiveTimeout;
var idleIntervalTimer;

function listenEvents() {
            idleIntervalTimer = setInterval(logoutTimeCounter, minInActiveTimeout * 60000); // multiple of 1 minute
            $('body').mousemove(function (e) {
                console.log(new Date($.now()) + " :: " + "Mouse Move"+idleTime);
                idleTime = minInActiveTimeout;
                clearInterval(idleIntervalTimer);
                idleIntervalTimer = setInterval(logoutTimeCounter, minInActiveTimeout * 60000);
            });
            $('body').keypress(function (e) {
                console.log(new Date($.now()) + " :: " + "Key Press"+idleTime);
                idleTime = minInActiveTimeout;
                clearInterval(idleIntervalTimer);
                idleIntervalTimer = setInterval(logoutTimeCounter, minInActiveTimeout * 60000);
            });
            $('body').click(function () {
                console.log(new Date($.now()) + " :: " + "Body Click"+idleTime);
                idleTime = minInActiveTimeout;
                clearInterval(idleIntervalTimer);
                idleIntervalTimer = setInterval(logoutTimeCounter, minInActiveTimeout * 60000);
            });
}


function logoutTimeCounter() {
            console.log(new Date($.now()) + " :: " + "idleTime  >>" + idleTime + "inActiveTimeout >>" + inActiveTimeout);
            if (idleTime === inActiveTimeout) {
                console.log(" <<Warning >>");
                $('#InactiveTimeoutModal').modal({backdrop: 'static', keyboard: false});
                $("#InactiveTimeoutModal").modal("show");
                clearInterval(idleIntervalTimer);
                setTimeout(logoutTimeCounter, 60000);
            }
            else if (idleTime > inActiveTimeout) { // 20 minutes
                console.log(new Date($.now()) + " :: " + "<< Time elapsed Hide and Logout>>");
                $("#InactiveTimeoutModal").modal("hide");
            }
            idleTime = idleTime + minInActiveTimeout;
}

谢谢

Answer 1

那应该执行Back-end。

如果不可能,,,您必须将用户事件监视为滚动，鼠标移动，单击。

var previous = 0;

document.addEventListener("mousemove", function(evt) {
 if(previous > 0) return;
 previous++;
});

document.addEventListener("click", function(evt) {
  if(previous > 0) return;
  previous++;
});

window.addEventListener("scroll", function(evt) {
  if(previous > 0) return;
  previous++;
});

//other event check..
//document.addEventListener....


setInterval(function(){
  if(previous > 0 )console.log("detect user action");
  else console.log("not detect user action");
},10000); 

Answer 2

有一种很好的方法（但你需要添加Jquery来绑定事件）：

var stop = false;
var initial_timer = (1000*15);
var timer = initial_timer;
var logoutUrl = 'unlock.html?last_page_visited='+window.location.pathname ; // URL to logout page.

function logOut(){
    window.location = logoutUrl;
}

if(!stop){
    setInterval(function(){
        timer-=1000;
        console.log("Timer:"+timer);
        if(timer==0 || timer<0){
            logOut()
            stop = true;
        }
    }, 1000);
}

$('body').bind('click dblclick mousedown mouseenter mouseleave keyup mouseover',
function(e){
    timer = initial_timer;
});

有关更多详细信息或完整示例：https://github.com/Sanix-Darker/LogOutTimer

在这里看到：https://jsbin.com/dabobil/edit?html,js,console,output