帮我解决这道数列题:
输入:
5
输出:
2
3 4
4 5 6
5 6 7 8
6 7 8 9 10
我的节目:
rows = 6 # number of rows in the pattern
start_num = 2 # starting number for the first row
for i in range(1,rows):
for j in range(i):
print(start_num, end=' ')
start_num += 1
print()
rows = 5
for i in range(rows+1):
for j in range(i):
print(i + j + 1, end=" ")
print()
你可以试试这个..
你可以用一个循环和
range()
函数来做到这一点:
rows = 6 # number of rows in the pattern
start_num = 2 # starting number for the first row
for i in range(rows):
print(*range(start_num+i, start_num+1+i+i))
*
函数前的range()
会将range()
函数的每次迭代展开成一个单独的参数给print()
.
认识到
i
行的第一个数字是1 + i
.for i in range(1, n_rows+1)
i
行有i
元素for j in range(first_num, first_num+i)
for i in range(1, n_rows+1):
first_number = 1 + i
for j in range(first_number, first_number + i):
print(j, end=" ")
print()
打印:
2
3 4
4 5 6
5 6 7 8
6 7 8 9 10