使用route param发布时无法将FileStream发送到AWS（无需正常工作）

Question

使用ASP.NET Core v.2.1.2和AWSSDK for S3（版本3.3.20.2）

相同的控制器，两个不同的路由（一个有url param而另一个没有）。方法是相同的，除了url param有一个参数。我想上传一个文件，然后将其发送到S3（这在无参数情况下工作正常）。

只是添加id参数会导致aws的请求因错误而超时：

"Your socket connection to the server was not read from or written to within the timeout period. Idle connections will be closed."

这是失败的请求：

curl -X POST \
  http://localhost:5000/api/post/image/4 \
  -H 'Cache-Control: no-cache' \
  -H 'Content-Type: application/x-www-form-urlencoded' \
  -H 'Postman-Token: c78c7572-8822-4de7-a532-61538df87c85' \
  -H 'content-type: multipart/form-data; boundary=----WebKitFormBoundary7MA4YWxkTrZu0gW' \
  -F =@/Users/myusername/Desktop/peace.png

我想添加id参数会改变HttpContext.Request.Body，但是当我在调试中运行并添加断点时，我看不到这种变化（流看起来完全一样）

我在这里错过了什么？相同的代码但删除了id param适用于两个路由

顺便说一下，我希望id param存在的原因是，一旦上传文件，我就可以在帖子上记录文件ID作为对AWS中记录的引用

using Microsoft.AspNetCore.Mvc;
using System;
using System.Collections.Generic;
using System.Linq;
using BlogApi.Models;
using BlogApi.Services;

namespace BlogApi.Controllers
{
  [Route("api/[controller]")]
  [ApiController]

  public class PostController : ControllerBase
  {
    public string AWS_KEY {get; private set;}
    public string AWS_SECRET {get; private set;}
    private readonly PostContext _context;
    private AmazonUploader uploader { get; set; }

    public PostController(PostContext context)
    {
      _context = context;
      AWS_KEY = "my_key";
      AWS_SECRET = "my_secret";
      uploader = new AmazonUploader(AWS_KEY, AWS_SECRET);
    }

    [HttpPost("image/{id}")]
    public string Image(long id)
    {
      var request = HttpContext.Request;
      var fileStream = request.Body;
      var contentLength = request.ContentLength;
      var contentType = request.ContentType;
      string key = Guid.NewGuid().ToString();

      var length = contentLength.HasValue ? (long)contentLength : 0;
      return uploader.sendMyFileToS3(fileStream, contentType, length, key).Result;
    }

    [HttpPost]
    public string MyFileUpload()
    {
      var request = HttpContext.Request;
      var fileStream = request.Body;
      var contentLength = request.ContentLength;
      var contentType = request.ContentType;
      string key = Guid.NewGuid().ToString();

      var length = contentLength.HasValue ? (long)contentLength : 0;
      return uploader.sendMyFileToS3(fileStream, contentType, length, key).Result;
    }
...

仅供参考，这是我的AmazonUploader类的代码

using System;
using System.Diagnostics;
using System.Net;
using System.Threading.Tasks;
using System.IO;
using Amazon;
using Amazon.S3;
using Amazon.S3.Model;
using Amazon.S3.Transfer;
using Microsoft.Extensions.Configuration;

namespace BlogApi.Services
{
  public class AmazonUploader
  {
    private IAmazonS3 client;
    private const string bucketName = "my_bucket"; 
    private static readonly RegionEndpoint bucketRegion = RegionEndpoint.EUWest2;

    public AmazonUploader(string AWS_KEY, string AWS_SECRET) {
      client = new AmazonS3Client(AWS_KEY, AWS_SECRET, bucketRegion);
    }

    public async Task<ListObjectsResponse> ListingObjectsAsync()
    {            
        ListObjectsRequest request = new ListObjectsRequest
        {
            BucketName = bucketName
        };
        return await client.ListObjectsAsync(request);
    }
    public async Task<string> sendMyFileToS3(System.IO.Stream inputStream, string contentType, long contentLength, string key)
    {
      PutObjectRequest request = new PutObjectRequest
      {
        BucketName = bucketName,
        Key = key,
        ContentType = contentType,
        InputStream = inputStream 
      };
      request.Headers.ContentLength = contentLength;
      PutObjectResponse awsResponse = await client.PutObjectAsync(request);
      if (awsResponse.HttpStatusCode == HttpStatusCode.OK) {
          return key;
      } else {
          return "error";
      }
    }
  }
}

Answer 1

我刚刚发现了问题

a）我犯了一个错误，并且不知何故Postman添加了一个额外的Content-Type标题：application / x-www-form-encoded

b）即使我没有错误地添加该标题，实际的内容类型也是错误的 - 我发送的是multipart / form-data，它不起作用 - 我需要将它作为二进制文件发送。如果我在Postman中为请求的Body选择了该选项，它就可以工作。