使用PHP从HTML表中读取数据

问题描述 投票:2回答:3

最近我有一个问题,我要做的是从HTML表读取数据并将数据抓取到一个名为$id的变量中。例如,我有这个代码:

<tr>
<td>413</td>
<td>Party Hat</td>
<td>0</td>
<td>No</td>
<td><a href="http://clubpenguincheatsnow.com/tools/swfviewer/items.swf?id=413">View SWF</a></td>
</tr>

我想要做的是另一个名为$array[$i]的变量,它持有一个搜索查询。我希望我的PHP代码在表中搜索,直到找到包含该特定查询的部分。在这种情况下,将是“党的帽子”。在找到查询之后我想要它做的是查看ID,这是“Party Hat”名称上方的“td”部分,在这种情况下ID是413.在此之后我想要变量$ id to持有身份证。我该怎么做呢?任何帮助将非常感谢!

php html web-scraping html-table scripting
3个回答
3
投票

使用TidyDOMDocumentDOMXPath(确保启用了PHP扩展),您可以执行以下操作:

<?php
$url = "http://example.org/test.html";

function get_data_from_table($id, $url)
{
    // retrieve the content of that url
    $content = file_get_contents($url);

    // repair bad HTML
    $tidy = tidy_parse_string($content);
    $tidy->cleanRepair();
    $content = (string)$tidy;

    // load into DOM
    $dom = new DOMDocument();
    $dom->loadHTML($content);

    // make xpath-able
    $xpath = new DOMXPath($dom);

    // search for the first td of each tr, where its content is $id
    $query = "//tr/td[position()=1 and normalize-space(text())='$id']";
    $elements = $xpath->query($query);
    if ($elements->length != 1) {
        // not exactly 1 result as expected? return number of hits
        return $elements->length;
    }

    // our td was found
    $element = $elements->item(0);

    // get his parent element (tr)
    $tr = $element->parentNode;
    $data = array();

    // iterate over it's td elements
    foreach ($tr->getElementsByTagName("td") as $td) {
        // retrieve the content as text
        $data[] = $td->textContent;
    }

    // return the array of <td> contents
    return $data;
}

echo '<pre>';
print_r(
    get_data_from_table(
        414,
        $url
    )
);
echo '</pre>';

您的HTML源代码(http://example.org/test.html):

<table><tr>
<td>413</td>
<td>Party Hat</td>
<td>0</td>
<td>No</td>
<td><a href="http://clubpenguincheatsnow.com/tools/swfviewer/items.swf?id=413">View SWF</a></td>
</tr><tr>
<td>414</td>
<td>Party Hat</td>
<td>0</td>
<td>No</td>
<td><a href="http://clubpenguincheatsnow.com/tools/swfviewer/items.swf?id=413">View SWF</a></td>
</tr>

(正如你所看到的,没有有效的HTML,但这没关系)


2
投票

这有效:(虽然有点难看,也许其他人可以提出更好的xpath解决方案)

$html = <<<HTML
<html>
    <body>
        <table>
            <thead>
                <tr>
                    <td>id</td>
                    <td>name</td>
                    <td>a</td>
                    <td>b</td>
                    <td>c</td>
                </tr>
            </thead>
            <tbody>
                <tr>
                    <td>413</td>
                    <td>Party Hat</td>
                    <td>0</td>
                    <td>No</td>
                    <td>a link</td>
                </tr>
                <tr>
                    <td>414</td>
                    <td>Party Hat 2</td>
                    <td>0</td>
                    <td>No</td>
                    <td>a link</td>
                </tr>
            </tbody>
        </table>
    </body>
</html>
HTML;

$doc = new DOMDocument();
$doc->loadHTML($html);
$domxpath = new DOMXPath($doc);

$res = $domxpath->query("//*[local-name() = 'td'][text() = 'Party Hat']/../td[position() = '1']");

var_dump($res->length, $res->item(0)->textContent);

输出:

INT(1) string(3)“413”


0
投票

尝试通过loadHTML将html加载到新的DOMDocument中,并像XML文档一样处理它,使用xpath或其他类型的查询

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