我想通过短信使用sim900a模块和arduino uno将gps坐标发送到特定号码,当他们从短信请求“SEND GPS”时,这里编写代码但是当我编译代码时我得到“错误:从'void'转换非标量类型'字符串'请求“.....请任何帮助表示赞赏...提前谢谢你
void loop() {
RecieveMessage();
if (sim.available() > 0)
{
Serial.write(sim.read());
}
if(sim.read()=="SEND GPS")
{
SendMessage();
}
}
void RecieveMessage()
{
Serial.println ("SIM800L Read an SMS");
sim.println("AT+CNMI=2,2,0,0,0");
Serial.write ("Unread Message done");
}
void SendMessage()
{
//Serial.println ("Sending Message");
sim.println("AT+CMGF=1");
sim.println("AT+CMGS=\"" + number + "\"\r");
while (sgps.available())
{
int c = sgps.read();
if (gps.encode(c))
{
float slat,slon;
String loc=gps.f_get_position(&slat, &slon);
}
String SMS = String("http://maps.google.com/maps?q=loc:")+String(loc);
sim.println(SMS);
sim.println((char)26);
}
gps.f_get_position
返回void,但你将它分配给String
。只需删除String loc=
void loop()
{
while(sgps.available())
{
int c = sgps.read();
if (gps.encode(c))
{
float slat,slon;
gps.f_get_position(&slat, &slon);
Serial.print("Latitude :");
Serial.println(slat, 6);
Serial.print("Longitude:");
Serial.println(slon, 6);
String loc = String(slat,6)+“”+ String(slon,6);
Serial.println(“发送消息”);
sim.println( “AT + CMGF = 1”); //在文本模式下设置GSM模块
延迟(1000);
Serial.println ("Set SMS Number");
sim.println("AT+CMGS=\"" + number + "\"\r"); //Mobile phone number to send message
delay(1000);
String SMS = String(“https://www.google.com/maps/”)+ String(slat,6)+“,”+ String(slon,6);
sim.println(SMS);
延迟(100);
sim.println((char)26); // CTRL + Z的ASCII码
延迟(1000);
_buffer = _readSerial();
}
}
}