我一直在研究一个小型的c ++应用程序,该应用程序与讲师和学生根据他们所授课/参加的课程而配对在一起。
[每位讲师都有一群学生。当学生上课与讲师讲授的课程相同时,我们会将同一名学生添加到该讲师中。
我有2个for循环,遍历所有讲师和学生,然后比较两者的班级,如果它们匹配,则将该学生添加到讲师中。
循环后,我循环浏览所有讲师,并获取每个讲师的人数。但是返回0,它应该返回1。(因为一位学生与每个讲师的班级相匹配)。
Lecturer.h
#pragma once
#include <iostream>
#include "Person.h"
#include "Student.h"
#include <vector>
#include <string>
using namespace std;
class Lecturer : public Person {
public:
// Lecturer(string department, string specialization, string name, int age, char gender)
// : department(department), specialization(specialization), name(name), age(age), gender(gender) {}
Lecturer() { }
Lecturer(string department, string specialization, string name, int age, char gender, string uniClass){
this->department = department;
this->specialization =specialization;
this->name = name;
this->age = age;
this->gender = gender;
this->uniClass = uniClass;
}
// Class Methods
void addStudent(Student student);
// Setter Methods
void setDepartment(string dprt);
void setSpecialization(string splz);
void setName(string nme);
void setAge(int ag);
void setGender(char g);
// Getter Methods
string getDepartment();
string getSpecialization();
string getUniClass();
int getStudentsSize();
vector<Student> getStudents();
private:
string department;
string specialization;
vector<Student> students;
string uniClass;
};
void Lecturer::addStudent(Student student)
{
cout << student.getName() << endl;
students.push_back(student);
}
int Lecturer::getStudentsSize()
{
return students.size();
}
Student.h
#pragma once
#include <iostream>
#include "Person.h"
#include <string>
using namespace std;
class Student : public Person {
public:
// Student(string major, string minor, int id, string name, int age, char gender)
// : major(major), minor(minor), id(id), name(name), age(age), gender(gender) {}
Student() { }
Student(string major, string minor, int id, string name, int age, char gender, string uniClass){
this->major = major;
this->minor = minor;
this->id = id;
this->name = name;
this->age = age;
this->gender = gender;
this->uniClass = uniClass;
}
// Setter Methods
void setMajor(string mjr);
void setMinor(string mnr);
void setId(int _id);
void setName(string nme);
void setAge(int ag);
void setGender(char g);
// Getter Methods
string getMajor();
string getMinor();
int getId();
string getUniClass();
string getName();
private:
string major;
string minor;
int id;
string uniClass;
};
string Student::getUniClass()
{
return uniClass;
}
main.cpp
#include <iostream>
#include <string>
#include "Person.h"
#include "Lecturer.h"
#include "Student.h"
int main()
{
vector<Lecturer> lecturers;
lecturers.push_back(Lecturer("Computing", "Advanced Programming", "John", 40, 'm', "AB101"));
lecturers.push_back(Lecturer("Business", "Finance", "Dave", 42, 'm', "AB102"));
lecturers.push_back(Lecturer("Science", "Physics", "Bill", 46, 'm', "AB103"));
vector<Student> students;
students.push_back(Student("Computer Science", "Maths", 123, "Mike", 20, 'm', "AB101"));
students.push_back(Student("Business", "Economics", 142, "Jane", 21, 'f', "AB102"));
students.push_back(Student("Engineering", "Physics", 151, "Mary", 19, 'f', "AB103"));
for(Lecturer lecturer : lecturers)
{
for(Student student : students)
{
//cout << "Name: " << student.getUniClass() << endl;
if (lecturer.getUniClass().compare(student.getUniClass()) == 0)
{
// ADDING A STUDENT THAT MATCHES THE CLASS
lecturer.addStudent(student);
}
}
}
for(Lecturer lecturer : lecturers)
{
// EACH LECTURER'S STUDENTS SIZE IS 0 HERE (SHOULD BE 1)
cout << lecturer.getStudentsSize() << endl;
}
}
您在各处使用值。这意味着副本。
您的第一个更改是使用references进行迭代。例如:
for (Lecturer& lecturer : lecturers)
// ^
每个讲师都有一个学生矢量。
为什么?每个讲师应有一个(n个无序)set学生。学生不会并行存在多次。而且,它们没有固有且相关的顺序。实际上,讲师为他们所教的每门课程都需要这样一套。
而且,为什么要假设每个学生都上一堂课? (查看源代码)啊!现在我懂了。
非常令人困惑。请解决此问题。如果使用适当的术语/名称和适当的数据结构,则不太可能会自己找出错误。
我有2个for循环,遍历所有讲师和学生,然后比较两者的班级,如果它们匹配,则将该学生添加到讲师中。
两个循环?太多了!最多只有一个循环。将内部循环替换为std::copy_if
的调用。这也可能有助于找到该错误。