当按下按钮时,我想处理那个函数调用,而不是在按钮所在的类中,而是在另一个类中。所以这里是我正在努力实现的以下代码:
class TestButton:
def __init__(self, root):
self.testButton = Button(root, text ="Test Button", command = testButtonPressed).grid(row = 11, column = 0)
#testButtonPressed is called in the TestButton class.
class TestClass:
#The testButtonPressed function is handled in the TestClass.
def testButtonPressed():
print "Button is pressed!"
请让我知道这是如何实现的,非常感谢你!
注意:我编辑了我的回复,因为我无法正确理解您的问题。
在python中你可以传递函数作为参数:
class TestButton:
def __init__(self, root, command):
self.testButton = Button(root, text ="Test Button", command = command).grid(row = 11, column = 0)
#testButtonPressed is called in the TestButton class.
class TestClass:
#The testButtonPressed function is handled in the TestClass.
def testButtonPressed(self):
print "Button is pressed!"
TestButton(root, TestClass().testButtonPressed)
如果已经定义了类并且您要传递的函数是静态的,那么您应该可以执行以下操作:
class TestClass:
def testButtonPressed(self):
print "Button is pressed!"
class TestButton:
def __init__(self, root):
self.testButton = Button(root, text="Test Button", command=TestClass.testButtonPressed).grid(row=11, column=0)
请记住:将函数作为参数传递时,需要删除括号'()'。如果不这样做,您将传递函数返回的内容,而不是函数本身。
.
如果要传递的函数不是静态的(需要在类的实例中调用),则必须具有对该实例的引用:
class TestClass:
def __init__(self):
self.message = "Button is pressed!"
def testButtonPressed(self):
print self.message
class TestButton:
def __init__(self, root):
instance = TestClass()
self.testButton = Button(root, text="Test Button", command=instance.testButtonPressed).grid(row=11, column=0)
或者,如果实例不在类的范围内:
instance = TestClass()
class TestButton:
def __init__(self, root, reference):
self.testButton = Button(root, text="Test Button", command=reference.testButtonPressed).grid(row=11, column=0)
test = TestButton(root, instance)
注意:非静态方法通常可以通过“自我”参数来识别:例如:
def function(self)