循环中的SUM值

Question

在我的PHP页面中，我有一个显示客户订单总数表的while循环。我想得到while循环中所有Totals值的总和。这就是我的代码的相关部分目前的样子：

<?php

include'includes/config.php';
$sql ="Select * from new_booking order by order asc";
$re = mysqli_query($mysqli,$sql);

while($row=mysqli_fetch_array($re)) { 
    $order    =   $row['order'];
    $duration =   12;
    $total = $order * $duration;

    echo " <p> $total </p>";
  // echo "<p> All Sumtotals should display here </p> ";

}

?> 

7 * 12 = 84 8 * 12 = 96 总和= 180

Answer 1

<?php

include'includes/config.php';
$sql ="Select * from new_booking order by order asc";
$re = mysqli_query($mysqli,$sql);
$total = 0;
while($row=mysqli_fetch_array($re)) { 
    $order    =   $row['order'];
    $duration =   12;
    $total = $total + ($order * $duration);


}

    echo " <p> $total </p>";
  // echo "<p> All Sumtotals should display here </p> ";

?> 

Answer 2

在循环中声明$ total out while循环为$ total = 0，在循环内写入$ total = $ total +（$ order * $ duration）

Answer 3

跟踪新变量中的总和..

<?php

include'includes/config.php';
$sql ="Select * from new_booking order by order asc";
$re = mysqli_query($mysqli,$sql);
$sumTotal = 0;

while($row=mysqli_fetch_array($re)) { 
    $order    =   $row['order'];
    $duration =   12;
    $total = $order * $duration;
    $sumTotal = $sumTotal + $total;
    echo " <p> $total </p>";
    echo " <p> Running total $sumTotal </p>";
}
echo " <p> Grand total $sumTotal </p>";
?> 

Answer 4

在循环之前定义一个变量，它将包含所有记录的总和：

$sumTotal = 0;

while($row = mysqli_fetch_array($re)) { 
    $order    = $row['order'];
    $duration = 12;
    $total    = $order * $duration;

    // Add this records total to the sum total
    $sumTotal += $total;

    echo "<p> $total </p>";
}    

echo "<p>Here's the sum total: $sumTotal</p>";

这将为您提供每条记录的总数，然后是之后所有记录的总和。

如果你想要查看每条记录的总和（看它增加），那么只需在循环中回显$sumTotal而不是$total。

Answer 5

如果你不需要一次打印出每一个，那么你可以在SQL语句中执行此操作，总结所有order值（* 12）并给它一个别名，以便更容易访问...

$sql = "SELECT SUM(`order` * 12) AS total FROM new_booking";
$run = mysqli_query($mysqli, $sql);
$row = mysqli_fetch_assoc($run);
echo $row['total'];