为什么ImageButton会在GridLayout中移出屏幕?

问题描述 投票:0回答:1

我的问题:一个ImageButton在GridLayout的屏幕之外。如何解决显示问题?我究竟做错了什么?

原图:

original picture

问题图片:

problem picture

这是我的代码:

@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);

LinearLayout linearLayout = new LinearLayout(this);
    linearLayout.setOrientation(LinearLayout.VERTICAL);
    LinearLayout.LayoutParams paramsLinLyt = new LinearLayout.LayoutParams(
            LinearLayout.LayoutParams.MATCH_PARENT, LinearLayout.LayoutParams.MATCH_PARENT);
    linearLayout.setLayoutParams(paramsLinLyt);

    GridLayout gridLayout = new GridLayout(this);
    gridLayout.setOrientation(GridLayout.VERTICAL);

    int rows = 4;
    int cols = 4;
    gridLayout.setRowCount(rows);
    gridLayout.setColumnCount(cols);

    ImageCropProcessor imageCropProcessor = new ImageCropProcessor();
    Bitmap[][] bitmaps = imageCropProcessor.cropImage(getResources(), R.drawable.tiger, rows, cols);

    for (int i = 0; i < rows; i++) {
        for (int j = 0; j < cols; j++) {
            GridLayout.Spec buttonRowSpec = GridLayout.spec(i);
            GridLayout.Spec buttonSpecColumn = GridLayout.spec(j);

            ImageButton imagebutton = new ImageButton(this);
            imagebutton.setId(j + 1 + (i * 4));
            imagebutton.setImageBitmap(bitmaps[i][j]);

            gridLayout.addView(imagebutton, new GridLayout.LayoutParams(buttonRowSpec, buttonSpecColumn));
        }
    }
linearLayout.addView(gridLayout);
setContentView(linearLayout);
}
java android bitmap
1个回答
1
投票

您的图片太大,无法放在屏幕上。

GridLayout的尺寸由它的内容决定。您尝试显示的内容太大,因此其中一部分位于可见屏幕之外。

您可以尝试缩放图像,使其适合屏幕。这样做时,应保留宽高比,以免图像被改变。

看看Bitmap.createScaledBitmap()

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