javascript日期（）按天，月，年计算老龄工作

Question

我想从用户的生日日期显示做那几日，月和年最后一次。 这里是我的代码，因为从这里取：Calculate age in JavaScript 它如何能够继续的月份和日期，如：

用户生日：2010/04/29 结果应该是这样的：2年，4月，5天之久。

function getAge(dateString) {
    var today = new Date();
    var birthDate = new Date(dateString);
    var age = today.getFullYear() - birthDate.getFullYear();
    var m = today.getMonth() - birthDate.getMonth();
    if (m < 0 || (m === 0 && today.getDate() < birthDate.getDate())) {
        age--;
    }
    return age;
}

alert(getAge('2010/04/29'));

但是：四联zxsw POI

Answer 1

http://jsfiddle.net/jFxb5/

function getAge(dateString) {
  var now = new Date();
  var today = new Date(now.getYear(),now.getMonth(),now.getDate());

  var yearNow = now.getYear();
  var monthNow = now.getMonth();
  var dateNow = now.getDate();

  var dob = new Date(dateString.substring(6,10),
                     dateString.substring(0,2)-1,                   
                     dateString.substring(3,5)                  
                     );

  var yearDob = dob.getYear();
  var monthDob = dob.getMonth();
  var dateDob = dob.getDate();
  var age = {};
  var ageString = "";
  var yearString = "";
  var monthString = "";
  var dayString = "";


  yearAge = yearNow - yearDob;

  if (monthNow >= monthDob)
    var monthAge = monthNow - monthDob;
  else {
    yearAge--;
    var monthAge = 12 + monthNow -monthDob;
  }

  if (dateNow >= dateDob)
    var dateAge = dateNow - dateDob;
  else {
    monthAge--;
    var dateAge = 31 + dateNow - dateDob;

    if (monthAge < 0) {
      monthAge = 11;
      yearAge--;
    }
  }

  age = {
      years: yearAge,
      months: monthAge,
      days: dateAge
      };

  if ( age.years > 1 ) yearString = " years";
  else yearString = " year";
  if ( age.months> 1 ) monthString = " months";
  else monthString = " month";
  if ( age.days > 1 ) dayString = " days";
  else dayString = " day";


  if ( (age.years > 0) && (age.months > 0) && (age.days > 0) )
    ageString = age.years + yearString + ", " + age.months + monthString + ", and " + age.days + dayString + " old.";
  else if ( (age.years == 0) && (age.months == 0) && (age.days > 0) )
    ageString = "Only " + age.days + dayString + " old!";
  else if ( (age.years > 0) && (age.months == 0) && (age.days == 0) )
    ageString = age.years + yearString + " old. Happy Birthday!!";
  else if ( (age.years > 0) && (age.months > 0) && (age.days == 0) )
    ageString = age.years + yearString + " and " + age.months + monthString + " old.";
  else if ( (age.years == 0) && (age.months > 0) && (age.days > 0) )
    ageString = age.months + monthString + " and " + age.days + dayString + " old.";
  else if ( (age.years > 0) && (age.months == 0) && (age.days > 0) )
    ageString = age.years + yearString + " and " + age.days + dayString + " old.";
  else if ( (age.years == 0) && (age.months > 0) && (age.days == 0) )
    ageString = age.months + monthString + " old.";
  else ageString = "Oops! Could not calculate age!";

  return ageString;
}


alert(getAge('09/09/1989'));

Answer 2

计算年龄的年，月，日的术语。输入任何有效的日期字符串格式的日期，如“1952年9月28日”，“1952年9月29日”，'09 /1952分之28' 等。

需要两个参数 - 出生日期，并在其上计算年龄的日期。您可以将第二个参数出来今天的日期。返回与年，月，随日龄属性的对象。

使用一年的365.2425天太阳年值。

出生@param生日日期。 @参数ageAtDate上计算年龄的日期。无为今天的日期。 @Returns {{年：数，月数：数，天：数}}

DEMO HERE

Answer 3

尝试这个：

function getAge(birthDate, ageAtDate) {
    var daysInMonth = 30.436875; // Days in a month on average.
    var dob = new Date(birthDate);
    var aad;
    if (!ageAtDate) aad = new Date();
    else aad = new Date(ageAtDate);
    var yearAad = aad.getFullYear();
    var yearDob = dob.getFullYear();
    var years = yearAad - yearDob; // Get age in years.
    dob.setFullYear(yearAad); // Set birthday for this year.
    var aadMillis = aad.getTime();
    var dobMillis = dob.getTime();
    if (aadMillis < dobMillis) {
        --years;
        dob.setFullYear(yearAad - 1); // Set to previous year's birthday
        dobMillis = dob.getTime();
    }
    var days = (aadMillis - dobMillis) / 86400000;  
    var monthsDec = days / daysInMonth; // Months with remainder.
    var months = Math.floor(monthsDec); // Remove fraction from month.
    days = Math.floor(daysInMonth * (monthsDec - months));
    return {years: years, months: months, days: days};
}

Answer 4

对于那些不想通过格式

function getAge(dateString) {
    var today = new Date();
    var DOB = new Date(dateString);
    var totalMonths = (today.getFullYear() - DOB.getFullYear()) * 12 + today.getMonth() - DOB.getMonth();
    totalMonths += today.getDay() < DOB.getDay() ? -1 : 0;
    var years = today.getFullYear() - DOB.getFullYear();
    if (DOB.getMonth() > today.getMonth())
        years = years - 1;
    else if (DOB.getMonth() === today.getMonth())
        if (DOB.getDate() > today.getDate())
            years = years - 1;

    var days;
    var months;

    if (DOB.getDate() > today.getDate()) {
        months = (totalMonths % 12);
        if (months == 0)
            months = 11;
        var x = today.getMonth();
        switch (x) {
            case 1:
            case 3:
            case 5:
            case 7:
            case 8:
            case 10:
            case 12: {
                var a = DOB.getDate() - today.getDate();
                days = 31 - a;
                break;
            }
            default: {
                var a = DOB.getDate() - today.getDate();
                days = 30 - a;
                break;
            }
        }

    }
    else {
        days = today.getDate() - DOB.getDate();
        if (DOB.getMonth() === today.getMonth())
            months = (totalMonths % 12);
        else
            months = (totalMonths % 12) + 1;
    }
    var age = years + ' years ' + months + ' months ' + days + ' days';
    return age;
}

console.log(getAge("2010/02/28"));
console.log(getAge("2010/03/01"));

限制谁，你可以更换：

mm/dd/yyyy

有：

var dob = new Date(dateString.substring(6,10),
                   dateString.substring(0,2)-1,                   
                   dateString.substring(3,5)                  
                  );

这让我用用2012/09/30，仍然可以得到正确的答案。

Answer 5

var dob = new Date(dateString);

Answer 6

当我看到了接受的解决方案的问题（见我的评论那里），我在这里提出我自己的版本，保证会有仅为1增加的出生日期时的天数没有“跳跃”。

此代码定义表示两个日期之间的差异更为通用

 function CalculateAge(DobString) {


        $("#age").val(getAge(DobString));
    }

     function getAge(dateString) {
            var now = new Date('2019/01/20');
            var today = new Date(now.getYear(), now.getMonth(), now.getDate());

            var yearNow = now.getYear();
            var monthNow = now.getMonth();
            var dateNow = now.getDate();

            var dob = new Date(dateString.substring(6, 10),
                               dateString.substring(3, 5) - 1,
                               dateString.substring(0, 2) 
                               );

            var yearDob = dob.getYear();
            var monthDob = dob.getMonth();
            var dateDob = dob.getDate();
            var age = {};
            var ageString = "";
            var yearString = "";
            var monthString = "";
            var dayString = "";


            yearAge = yearNow - yearDob;

            if (monthNow >= monthDob)
                var monthAge = monthNow - monthDob;
            else {
                yearAge--;
                var monthAge = 12 + monthNow - monthDob;
            }

            if (dateNow >= dateDob)
                var dateAge = dateNow - dateDob;
            else {
                monthAge--;
                var dateAge = 31 + dateNow - dateDob;

                if (monthAge < 0) {
                    monthAge = 11;
                    yearAge--;
                }
            }

            age = {
                years: yearAge,
                months: monthAge,
                days: dateAge
            };

            if (age.years > 1) yearString = " years";
            else yearString = " year";
            if (age.months > 1) monthString = " months";
            else monthString = " month";
            if (age.days > 1) dayString = " days";
            else dayString = " day";


            if ((age.years > 0) && (age.months > 0) && (age.days > 0))
                ageString = age.years + yearString + ", " + age.months + monthString + " " + age.days + dayString + " ";
            else if ((age.years == 0) && (age.months == 0) && (age.days > 0))
                ageString = " " + age.days + dayString + " ";
            else if ((age.years > 0) && (age.months == 0) && (age.days == 0))
                ageString = age.years + yearString + " ";
            else if ((age.years > 0) && (age.months > 0) && (age.days == 0))
                ageString = age.years + yearString + "  " + age.months + monthString + " ";
            else if ((age.years == 0) && (age.months > 0) && (age.days > 0))
                ageString = age.months + monthString + " " + age.days + dayString + " ";
            else if ((age.years > 0) && (age.months == 0) && (age.days > 0))
                ageString = age.years + yearString + " " + age.days + dayString + " ";
            else if ((age.years == 0) && (age.months > 0) && (age.days == 0))
                ageString = age.months + monthString + " ";
            else ageString = "Oops! Could not calculate age!";

            return ageString;
        }

类。功能DateInterval然后成为基于该类薄的实现。

getAge