将纪元时间完全手动转换为日期和时间

问题描述 投票:0回答:3

我编写了这个 Perl 脚本来将文件中的日期和时间转换为纪元时间。

原始日期格式为

dd-mm-yyyy hh:MM:ss

我这样做的原因是因为我必须将这些值写入数据库,并且列只接受整数值。

use strict;
use warnings;
use Time::Local;

$datestring = '07-06-2019 21:13:00';

my ($dd, $mm, $yyyy, $hh, $min, $sec) = split /\W+/, $datestring;

my $epoch = timelocal($sec,$min,$hh,$dd,$mm-1,$yyyy-1900);
print("$epoch\n");

将日期

07-06-2019 21:13:00
翻译为
1559934780

问题: 这些值现在显示在用户无法读取的前端中,前端没有脚本实用程序,我只能使用许多不同的计算公式来使其可读。

是否有一种完全手动的方法,只需使用计算器/计算即可将纪元时间转换回用户可读的日期和时间?

perl epoch
3个回答
3
投票

核心Time::Piece可以根据您当地的时区进行双向转换。

use strict;
use warnings;
use Time::Piece;

my $datestring = '07-06-2019 21:13:00';
my $time = localtime->strptime($datestring, '%d-%m-%Y %H:%M:%S');
my $epoch = $time->epoch;

...

my $time = localtime($epoch);
my $datestring = $time->strftime('%d-%m-%Y %H:%M:%S');

请参阅任何标准 strftime 或 strptime 手册页,了解通常接受的格式说明符 - 不幸的是,Time::Piece 接受的格式说明符没有记录在案。


如果不访问 Perl 5.10 以来的核心 Time::Piece,您可以使用内置的 localtime 函数,它只是稍微复杂一点(如 timelocal)。

use strict;
use warnings;
my $epoch = 1559934780;
my ($sec,$min,$hour,$mday,$mon,$year,$wday,$yday,$isdst) = localtime $epoch;
my $date_string = sprintf '%02d-%02d-%04d %02d:%02d:%02d',
  $mday, $mon+1, $year+1900, $hour, $min, $sec;

3
投票

在 DateTime.pm 的早期版本中,您会发现一个子 _rd2greg,它是我为 Rich Bowen 早期且长期不存在的 Project Reefknot 编写的 jd2greg。这需要从 1 年初开始的几天,并生成年、月和日。您可以将纪元时间除以 86400(一天中的秒数),然后添加 719163(截至 1970 年的天数)来传递给它。

这里是jd2greg和对应的greg2jd:

=head2 jd2greg

    ($year, $month, $day) = jd2greg( $jd );

    Convert number of days on or after Jan 1, 1 CE (Gregorian) to
    gregorian year,month,day.

=cut

sub jd2greg {
    use integer;
    my $d = shift;
    my $yadj = 0;
    my ( $c, $y, $m );

    # add 306 days to make relative to Mar 1, 0; also adjust $d to be within
    # a range (1..2**28-1) where our calculations will work with 32bit ints
    if ( $d > 2**28 - 307 ) {

        # avoid overflow if $d close to maxint
        $yadj = ( $d - 146097 + 306 ) / 146097 + 1;
        $d -= $yadj * 146097 - 306;
      } elsif ( ( $d += 306 ) <= 0 )
    {
        $yadj =
          -( -$d / 146097 + 1 );    # avoid ambiguity in C division of negatives
        $d -= $yadj * 146097;
    }

    $c =
      ( $d * 4 - 1 ) / 146097;    # calc # of centuries $d is after 29 Feb of yr 0
    $d -= $c * 146097 / 4;    #     (4 centuries = 146097 days)
    $y = ( $d * 4 - 1 ) / 1461;    # calc number of years into the century,
    $d -= $y * 1461 / 4;    #     again March-based (4 yrs =~ 146[01] days)
    $m =
      ( $d * 12 + 1093 ) / 367;    # get the month (3..14 represent March through
    $d -= ( $m * 367 - 1094 ) / 12;    #     February of following year)
    $y += $c * 100 + $yadj * 400;    # get the real year, which is off by
    ++$y, $m -= 12 if $m > 12;         #     one if month is January or February
    return ( $y, $m, $d );
}


=head2 greg2jd

    $jd = greg2jd( $year, $month, $day );

    Convert gregorian year,month,day to days on or after Jan 1, 1 CE
    (Gregorian).  Normalization is performed (e.g. month of 28 means
    April two years after given year) for month < 1 or > 12 or day < 1
    or > last day of month.

=cut

sub greg2jd {
    use integer;
    my ( $y, $m, $d ) = @_;
    my $adj;

    # make month in range 3..14 (treat Jan & Feb as months 13..14 of prev year)
    if ( $m <= 2 ) {
        $y -= ( $adj = ( 14 - $m ) / 12 );
        $m += 12 * $adj;
      } elsif ( $m > 14 )
    {
        $y += ( $adj = ( $m - 3 ) / 12 );
        $m -= 12 * $adj;
    }

    # make year positive (oh, for a use integer 'sane_div'!)
    if ( $y < 0 ) {
        $d -= 146097 * ( $adj = ( 399 - $y ) / 400 );
        $y += 400 * $adj;
    }

    # add: day of month, days of previous 0-11 month period that began w/March,
    # days of previous 0-399 year period that began w/March of a 400-multiple
    # year), days of any 400-year periods before that, and 306 days to adjust
    # from Mar 1, year 0-relative to Jan 1, year 1-relative (whew)

    $d += ( $m * 367 - 1094 ) / 12 + $y % 100 * 1461 / 4 +
      ( $y / 100 * 36524 + $y / 400 ) - 306;
}

0
投票

只是一个快速说明:这里有一个快速实用函数,可以根据实际定义生成一些关键常量,而不必硬编码这么多常量:


function _() {
    return \
        DAYS_IN_400YRS =  4 * (\
        DAYS_IN_100YRS = 25 * (\
        DAYS_IN_4_YRS  =  4 * (\
        DAYS_IN_CMMNYR =  8 * (8 * (5) + 5) + 5 \
                               ) +  1) - 1) + 1
}'

146097

DAYS_IN_400YRS: 146097
DAYS_IN_100YRS:  36524
DAYS_IN_4_YRS:    1461
DAYS_IN_CMMNYR:    365

或者如果你想做得非常全面:

function __() {

   return \
     _SECS_IN_400YRS      =      (\ 
     _DAYS_IN_400YRS      =  4 * (\
     _DAYS_IN_100YRS      = 25 * (\
     _DAYS_IN_4_YRS       =  4 * (\
     _DAYS_IN_CMMNYR      =      (\
     _DT_LONG_MNTHS_IN_YR = 7) * (\
            _DAYS_IN_LONG_MNTH = (\
        _DAYS_IN_SHRT_MNTH     = (\
        _DAYS_IN_LEAP_FEBR     = (\
        _DAYS_IN_CMMN_FEBR     = (\
             _DT_WEEKS_IN_FEB  = 4 ) * (\
             _DT_DAYS_IN_WEEK  = 7 )) + 1 ) + 1 ) + 1 ) + (\
        _DT_STND_MNTHS_IN_YR   = 4 ) * \
             _DAYS_IN_SHRT_MNTH + \
             _DAYS_IN_CMMN_FEBR )     + 1 ) - 1 ) + 1 ) \
                   * (\
     _SECS_IN_DY = (_TM_HRS_IN_DY = 24 ) * (\
     _SECS_IN_HR = (_TM_MNS_IN_HR = 60 ) * (\
     _SECS_IN_MN =                  60 ) ) )
}

_DAYS_IN_400YRS:        146097
_DAYS_IN_100YRS:         36524
_DAYS_IN_4_YRS:           1461
_DAYS_IN_CMMNYR:           365

_DAYS_IN_LONG_MNTH:         31
_DAYS_IN_SHRT_MNTH:         30
_DAYS_IN_LEAP_FEBR:         29
_DAYS_IN_CMMN_FEBR:         28

_DT_DAYS_IN_WEEK:            7
_DT_WEEKS_IN_FEB:            4
_DT_STND_MNTHS_IN_YR:        4
_DT_LONG_MNTHS_IN_YR:        7

  _SECS_IN_400YRS: 12622780800

  _SECS_IN_DY:           86400
  _SECS_IN_HR:            3600
  _SECS_IN_MN:              60
_TM_MNS_IN_HR:              60
_TM_HRS_IN_DY:              24
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