删除列中某个字符后的计数-SQL

Question

我有一个包含以下数据的表（staffs_table）；

name               profession
------------------------------
Corbin             Human Resources|Accountant
Cort               Programmer|Receptionist|Helpdesk

我希望每个职业count个人数，以便使我的结果如下；

profession             number_of_staffs
---------------------------------------
Human Resources            1
Accountant                 1 
Programmer                 1
Receptionist               1
Helpdesk                   1

我尝试了以下SQL查询，但没有成功；

SELECT profession, COUNT(*) AS number_of_staffs FROM staffs_table GROUP BY profession ORDER BY COUNT(*) DESC;

输出：

profession                   number_of_staffs
---------------------------------------------
Human Resources|Accountant            1
Programmer|Receptionist|Helpdesk      1 

也尝试了以下；

SELECT staffs_table.name,
SUBSTRING_INDEX(SUBSTRING_INDEX(staffs_table.profession, '|', numbers.n), '|', -1) profession
FROM
  numbers INNER JOIN staffs_table
  ON CHAR_LENGTH(staffs_table.profession)
     -CHAR_LENGTH(REPLACE(staffs_table.profession, '|', ''))>=numbers.n-1

输出：

name               profession
------------------------------
Corbin             Human Resources
Corbin             Accountant
Cort               Programmer
Cort               Receptionist
Cort               Helpdesk

提前感谢！

Answer 1

SELECT jsontable.profession, COUNT(jsontable.profession) number_of_staffs
FROM staffs_table
CROSS JOIN JSON_TABLE( CONCAT('["', REPLACE(staffs_table.profession, '|', '","'), '"]'),
                       "$[*]" COLUMNS( profession VARCHAR(254) PATH "$" )
                     ) AS jsontable
GROUP BY jsontable.profession;

fiddle