为什么执行这些表时会出现错误1452? [重复]

问题描述 投票:0回答:1

我想在一些表中插入一些数据。但是,到达statistics_per_year后,mysql会弹出错误代码1452,但我不知道为什么会这样。

错误:

17:54:58    INSERT INTO statistics_per_year(disease_continent_id,infected_id,dead_id) VALUES(2,3,4) Error Code: 1452. Cannot add or update a child row: a foreign key constraint fails (`practice`.`statistics_per_year`, CONSTRAINT `statistics_per_year_ibfk_1` FOREIGN KEY (`infected_id`) REFERENCES `statistics_reference` (`infected_id`))    0.484 sec

代码:

CREATE TABLE df(
    disease_continent_id INT NOT NULL PRIMARY KEY 
);
CREATE TABLE statistics_reference(
    infected_id INT NOT NULL,
    dead_id INT NOT NULL,
    per_100000_population VARCHAR(30) NOT NULL,
    PRIMARY KEY(infected_id)
);
CREATE TABLE statistics_per_year(
    disease_continent_id INT NOT NULL,
    infected_id INT NOT NULL,
    dead_id INT NOT NULL,
    FOREIGN KEY(infected_id) REFERENCES statistics_reference(infected_id),
    FOREIGN KEY(disease_continent_id) REFERENCES df(disease_continent_id)
);
INSERT INTO df(disease_continent_id)
VALUES(1);
INSERT INTO statistics_reference(infected_id,dead_id,per_100000_population)
VALUES(1,2,"fff");
INSERT INTO statistics_per_year(disease_continent_id,infected_id,dead_id)
VALUES(1,3,4);
mysql foreign-keys primary-key composite-primary-key mysql-error-1452
1个回答
0
投票

您的模式停留:

CREATE TABLE statistics_per_year(
    ...
    FOREIGN KEY(infected_id) REFERENCES statistics_reference(infected_id),
    ...
);       

这意味着:您在statistics_per_year(infected_id)中插入的每个值都必须在statistics_reference(infected_id)中。


您愿意:

INSERT INTO statistics_reference
    (infected_id,dead_id,per_100000_population) 
    VALUES(1,2,"fff");
INSERT INTO statistics_per_year
    (disease_continent_id,infected_id,dead_id) 
    VALUES(1,3,4);

statistics_reference仅包含一个记录,并带有infected_id = 1。您正在尝试使用statistics_per_year在相关表infected_id = 3中插入一条记录。失败是因为statistics_reference中没有该值的父记录。

您可以在statistics_reference中插入丢失的父记录,或在子表中更改insert以引用现有的父ID。

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