HttpClient从Request.Form .NET Core复制数据

问题描述 投票:0回答:1

我有包含表格数据和文件的POST查询,我需要将相同的数据发送到另一个POST请求。我将用于此HttpClient类。

是否可以复制所有Request.Form数据并将其插入新请求?还是我需要添加每个参数?

我的意思是这样的:

var httpClient = new HttpClient();
var httpResponseMessage = await httpClient.PostAsync("some_url", Request.Form);
.net-core asp.net-core-webapi dotnet-httpclient
1个回答
0
投票

是否可以复制所有Request.Form数据并将其插入到新请求中?还是我需要添加每个参数?

您需要添加如下所示的每个参数:

ProjectA中的模型:

public class FormData
{
    public int Id { get; set; }
    public IFormFile File { get; set; }
    public string Name { get; set; }
}

在ProjectA中查看:

@model FormData
<form asp-action="Post" enctype="multipart/form-data">
    <div>
        Id:<input asp-for="Id"/>
    </div>
    <div>
        Name:<input asp-for="Name"/>
    </div>
    <div>
        FIle:<input asp-for="File" />
    </div>
    <div>
        <input type="submit" value="create" />
    </div>
</form>

ProjectA中的控制器:

[HttpPost]
public async Task<IActionResult> Post(FormData formData)
{
    HttpClient client = new HttpClient();
    // var formData = HttpContext.Request.Form;
    client.BaseAddress = new Uri("http://localhost:63331");//your applicationUrl
    client.DefaultRequestHeaders.Accept.Clear();

    var multiContent = new MultipartFormDataContent();

    var file = formData.File;
    if (file != null)
    {
        var fileStreamContent = new StreamContent(file.OpenReadStream());
        multiContent.Add(fileStreamContent, "File", file.FileName);
    }

    multiContent.Add(new StringContent(formData.Id.ToString()), "id");
    multiContent.Add(new StringContent(formData.Name.ToString()), "name");


    var response = await client.PostAsync("/api/values", multiContent);
    //do your stuff...
    return Ok();
}

ProjectB中的模型:

public class FormDataModel
{
    public int Id { get; set; }
    public IFormFile File { get; set; }
    public string Name { get; set; }
}

ProjectB中的控制器:

[HttpPost]
public void Post([FromForm]FormDataModel model)
{
      //...
}

结果:enter image description here

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