使用PHP和mySql从下拉菜单中选择选项

问题描述 投票:0回答:2

我试图从MySQL数据库创建一个简单的选择下拉菜单。但是,它不适用于我的代码。

这是我的代码:

            <?php
              mysql_select_db($database_conn, $conn);
              $query_RsCourse = "SELECT * FROM tbl_course ORDER BY courseid DESC";
              $RsCourse = mysql_query($query_RsCourse, $conn) or die(mysql_error());
              $totalRows_RsCourse = mysql_num_rows($RsCourse);
              $count=0;
              while ( $row = mysql_fetch_array($RsCourse, MYSQL_ASSOC)) {
              $courseid=$row["courseid"];
         $count++;  
              }
             ?>

            <tr>
            <td bgcolor="#CCCCCC">&nbsp;Course Name</td>
            <td bgcolor="#dfdfdf">&nbsp;<select name="courseid">
            <option value="" SELECTED>Selected Course</option>      
            <option value="<?php echo $courseid; ?>"><?php echo $row_RsCourse['$courseid']; ?></option>
            </select>
            </td>
            </tr>

任何建议将被认真考虑!

php mysql select drop-down-menu option
2个回答
0
投票
 <?php

 echo '<tr>
        <td bgcolor="#CCCCCC">&nbsp;Course Name</td>
        <td bgcolor="#dfdfdf">&nbsp;';

        mysql_select_db($database_conn, $conn);
        $query_RsCourse = "SELECT * FROM tbl_course ORDER BY courseid DESC";
        $RsCourse = mysql_query($query_RsCourse, $conn) or die(mysql_error());
        $totalRows_RsCourse = mysql_num_rows($RsCourse);
        if($totalRows_RsCourse)
        {
        echo '<select name="courseid"><option value="" SELECTED>Selected Course</option>';
            $count=0;

            while ($row = mysql_fetch_array($RsCourse, MYSQL_ASSOC))
            {
            $count++;
            echo '<option value="'.$row['courseid'].'">'.$row['courseid'].'</option>';
            }
            echo '</select>';
        }
        else
        {
        echo 'No courses to show yet.'; // no rows in tbl_course
        }
        echo '</td>
            </tr>';

?>

那是一团糟,但希望你能从这些新代码中继续下去。请享用。

PS:这部分>'.$row['courseid'].'</option>你可以根据你的表结构更改为新的一个,这里没有显示。

<?php

 echo '<tr>
        <td bgcolor="#CCCCCC">&nbsp;Course Name</td>
        <td bgcolor="#dfdfdf">&nbsp;';

        mysql_select_db($database_conn, $conn);
        $query_RsCourse = "SELECT * FROM tbl_course ORDER BY courseid DESC";
        $RsCourse = mysql_query($query_RsCourse, $conn) or die(mysql_error());
        $totalRows_RsCourse = mysql_num_rows($RsCourse);


        echo '<select name="courseid"><option value="" SELECTED>Selected Course</option>';
            $count=0;

            while ($row = mysql_fetch_array($RsCourse, MYSQL_ASSOC))
            {
            $count++;
            echo '<option value="'.$row['courseid'].'">'.$row['courseid'].'</option>';
            }
            echo '</select></td>
            </tr>';

?>

0
投票

您可以将所有内容存储在缓冲区中,并在下面的选择中一次打印:

    <?php
      mysql_select_db($database_conn, $conn);
      $query_RsCourse = "SELECT * FROM tbl_course ORDER BY courseid DESC";
      $RsCourse = mysql_query($query_RsCourse, $conn) or die(mysql_error());
      $coursesHtml = "";
      while ( $row = mysql_fetch_array($RsCourse, MYSQL_ASSOC)) {
        $coursesHtml .= "<option value='{$row["courseid"]}'>{$row["coursename"]}</option>";
      }
     ?>

    <tr>
    <td bgcolor="#CCCCCC">Course Name</td>
    <td bgcolor="#dfdfdf">
    <select name="courseid">
    <option value="" SELECTED>Selected Course</option>      
    <?= $coursesHtml  ?>
    </select>
    </td>
    </tr>

PS:避免使用&nbsp;,使用padding-left: 5px;或其他功能使用css设置你的html样式;

PS2:您不应该使用表格结构显示您的页面/表单,使用带有flexbox的div。

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