我必须在退出循环之前按 0 两次,我需要打印平均工资和 5k 以内的所有工资。帮助新手?!
#此程序将员工姓名后跟他们的薪水作为输入 #使用标记值,用户可以继续输入姓名和薪水,直到 #按 0 退出。然后它应该打印平均工资和数组的内容。
#我的代码很草率。我会接受改进建议。谢谢!
from statistics import mean
import sys
names = []
salaries = []
e = None
s = None
running = True
def Main():
e = None
s = None
count = 1
while running == True:
e = input(f"Enter Employee {count} Name (press 0 to quit): ")
s = float(input(f"Enter Employee {count} salary (in hundreds) (press 0 to quit): "))
L = [e, s]
if e == 0 or s == 0:
print(names)
sys.exit()
# print(statistics.mean(names))
count = count + 1
# print(statistics.mean(namees.append(L)))
salaries.append(L)
主要()
可能是我的方法不是100%专业,还是保留你的sys.exit()。我假设您在代码中的某处将
running
设置为 true,如果是这样,请删除我在函数中的第一行。
def Main():
running = True
e = None
s = None
count = 1
while running == True:
e = input(f"Enter Employee {count} Name (press 0 to quit): ")
s = float(input(f"Enter Employee {count} salary (in hundreds) (press 0 to quit): "))
L = [e, s]
# e is str
if e == '0' or s == 0:
print(names)
# this will break while loop
running = 0 # or False