TableView重新实现QAbstractTableModel后在表中无数据显示

问题描述 投票:0回答:1

我无法获取要在我的QML TableView上显示的数据。我定义了两个数组-标头和行,它们希望在TableView上显示,但到目前为止没有成功。下面是最小的可复制示例。

engine.py

import os
import sys
from PySide2 import QtCore, QtGui, QtSql, QtQml
from Table import TbModel
from PySide2.QtWidgets import QApplication
if __name__ == "__main__":
    current_dir = os.path.dirname(os.path.realpath(__file__))
    app = QApplication(sys.argv)
    QtQml.qmlRegisterType(TbModel, "TbModel", 1, 0, "TbModel")
    engine = QtQml.QQmlApplicationEngine()
    qml_path = os.path.join( "main.qml")
    engine.load(QtCore.QUrl.fromLocalFile(qml_path))
    if not engine.rootObjects():
        sys.exit(-1)
    sys.exit(app.exec_())

main.qml

import QtQuick 2.13
import QtQuick.Window 2.2
import QtQuick.Controls 2.5
import QtQuick.Controls 1.4
import QtQuick.Controls 2.13
import TbModel 1.0

ApplicationWindow {
    visible: true
    id: window
    width: Screen.width
    height: Screen.height
    Grid {

    width: 300
    height: 100
    visible: true
    spacing: 200
    TableView
    {
        id: idtable
        model: TbModel { }
    TableViewColumn {
        role: "sci" 
        title: "sci"
    }
    TableViewColumn {
        role: "year"
        title: "year"
    }
    TableViewColumn {
        role: "cont"
        title: "cont"
    }

        // Component.onCompleted: {

        //     var roles = model.roleNameArray()
        //                 for (var i = 0; i < model.columnCount(); i++)
        //     {
        //         var column = addColumn( Qt.createQmlObject(
        //             "import QtQuick.Controls 1.1; TableViewColumn {}",
        //             this) )
        //         column.role=roles[i]
        //         column.title=roles[i]

        //     }
        // }
    }

}
}

Table.py

from PySide2.QtCore import QAbstractTableModel, QModelIndex, QObject, Qt
from PySide2 import QtCore

class TbModel(QAbstractTableModel):
    def __init__(self, parent: QObject = None) -> None:
        super().__init__(parent)
        self.headers = ["sci", "year", "cont"]
        self.rows =    [("Newton", "1643-01-04", "Classical mechanics"),
           ("Einstein", "1879-03-14", "Relativity"),
           ("Darwin", "1809-02-12", "Evolution")]

    def rowCount(self, parent=QModelIndex()):
        return len(self.rows)

    def columnCount(self, parent=QModelIndex()):
        return len(self.headers)

    def data(self, index, role):
        if role != Qt.DisplayRole:
            return None
        return self.rows[index.row()][index.column()]

    def headerData(self, section, orientation, role) :
        if role != Qt.DisplayRole:
            return None

        if section < 0 or section >= len(self.headers):
            return None

        return self.headers[section]

    def roleNames(self):
        roles = {
            Qt.UserRole + 1 : 'sci',
            Qt.UserRole + 2 : 'year',
            Qt.UserRole + 3 : 'cont'
        }
        return roles


    @QtCore.Slot(result="QVariantList")
    def roleNameArray(self):
        names = []
        names=self.headers

        return names

我可以在TableView中选择行,但是看不到数据。任何帮助表示赞赏。

python qt qml pyside2
1个回答
0
投票

您的代码有2个错误:

  • 在C ++中roleNames()方法返回QHash<int, QByteArray>,因此在Python中,您必须返回其键为整数且值必须为bytesQByteArray的字典,但是在您的情况下,值是字符串。

  • 数据方法必须提供视图所需的信息,在这种情况下,它们是与[sci],[year]和[cont]关联的角色,其值分别为Qt.UserRole + 1Qt.UserRole + 2和[C0 ]与Qt.UserRole + 3不同,但在您的逻辑中,除Qt.DisplayRole以外的任何值都将与上述内容无矛盾。

更正前2个错误,然后的解决方法是:

Qt.DisplayRole
def data(self, index, role=Qt.DisplayRole):
    if 0 <= index.row() < self.rowCount():
        if 0 <= index.column() < self.columnCount():
            if role in self.roleNames():
                return self.rows[index.row()][index.column()]
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