将curl请求转换为groovy / grails HTTPBuilder请求

Question

我正在做一个curl请求:-

curl -X POST -H“内容类型：application/json”-H“接受：application/json，文本/javascript”-d'[{“command”：“system.login”，“password”：“guesswhatIam ", "user": "theuser"}]' -k "https://TheIpAddress/ajax?sid="

我从curl得到的回应是：-

[{“状态”：“确定”，“sid”：“7dfb39fd-2945-46d8-9036-81bb4ff2d858”，“死区时间”：0}]

我正在尝试找出如何使用 HTTPBuilder 在 Grails 中执行等效操作，并且我非常想提取该 sid 值。

我已经尝试过这个:-

    def http = new HTTPBuilder ('https://' + ipAddress+'/ajax?sid=')
    http.ignoreSSLIssues()
    http.headers = [Accept: 'application/json,text/javascript', charset: 'UTF-8', ContentType: 'application/json' ]
    http.request(POST) {
        uri.path = ''
        body = ['[{"command": "system.login", "password": "thepassword", "user": "theuser"}]']
        requestContentType = ContentType.JSON
        response.success = { resp,json ->
            print "Success! ${resp.status}"
            print json
        }

        response.failure = { resp ->
            println "Request failed with status ${resp.status}"
        }
    }

我获得了 200 成功，但我似乎无法解析我得到的数据 - 我似乎得到了 null？

如有任何指点，我们将不胜感激。

Answer 1

所以，最终我放弃了 HTTPBuilder，转而使用 Java。这对我有用:-

    import java.io.IOException;
    import java.io.InputStream;
    import java.io.OutputStreamWriter;
    import java.net.HttpURLConnection;
    import java.net.URL;
    import java.util.Scanner;

    URL url = new URL("http://" + ipAddress + "/ajax?sid=");
    HttpURLConnection httpConn = (HttpURLConnection) url.openConnection();
    httpConn.setRequestMethod("POST");
    httpConn.setRequestProperty("Content-Type", "application/json");
    httpConn.setRequestProperty("Accept", "application/json,text/javascript");
    httpConn.setDoOutput(true);
    OutputStreamWriter writer = new OutputStreamWriter(httpConn.getOutputStream());        
    writer.write("[{\"command\": \"system.login\", \"password\": \"thePassworrd\", \"user\": \"theUser\"}]");
    writer.flush();
    writer.close();
    httpConn.getOutputStream().close();
    InputStream responseStream = httpConn.getResponseCode() / 100 == 2
            ? httpConn.getInputStream()
            : httpConn.getErrorStream();
    Scanner s = new Scanner(responseStream).useDelimiter("\\A");
    String response = s.hasNext() ? s.next() : "";
    return response;

我希望这可以帮助其他有类似问题的人。