如上一个问题所建议，我将尽力澄清我想要实现的目标。像在file1中一样，在$ 4列中，我的数字不是像1,2,3,4,5那样连续排列的。我需要打印那些丢失的东西，例如在3号之后，我应该得到4号，依此类推
猫文件1
A R5 A48 1
B R5 A48 2
C R4 A48 3
D R8 A48 15
E R9 A48 22
F R20 B55 21
G R55 B22 19
R B1 I77 14
AA B8 PP 18
BX A255 PA 7
CA A77 PB 10
WW W7 PX 11
我在此awk班轮返航中找到了部分解决方案
arr=($(awk '{ print $4 }' file1 )) | printf '%s\n' ${arr[*]}| \
awk -v first=1 -v last=23 ' BEGIN {for(i=first; i<=last; i++) array[i] = 1} \
{for(i=1;i<=NF;i++) array[$i] += 1} END {for (num in array) if (array[num] == 0) print num}'
4
5
6
8
9
12
13
16
17
20
23
这是我想要的，但我仍然缺少23号之后直到31号为止的剩余编号，并基于file2行/行数将其粘贴为$ 3列（3号）
cat file2
md5sum 25d422cc23b44c3bbd7a66c76d52af46
md5sum 25d422cc23b44c3bbd7a66c76d52af47
md5sum 25d422cc23b44c3bbd7a66c76d52af48
md5sum 25d422cc23b44c3bbd7a66c76d52af41
md5sum 25d422cc23b44c3bbd7a66c76d52af22
md5sum 25d422cc23b44c3bbd7a66c76d52af33
md5sum 25d422cc23b44c3bbd7a66c76d52af12
md5sum 25d422cc23b44c3bbd7a66c76d52af01
md5sum 25d422cc23b44c3bbd7a66c76d52af55
md5sum 25d422cc23b44c3bbd7a66c76d52af14
md5sum 25d422cc23b44c3bbd7a66c76d52af18
md5sum 25d422cc23b44c3bbd7a66c76d52af17
md5sum 25d422cc23b44c3bbd7a66c76d52af77
md5sum 25d422cc23b44c3bbd7a66c76d52af06
md5sum 25d422cc23b44c3bbd7a66c76d52af05
md5sum 25d422cc23b44c3bbd7a66c76d52af72
md5sum 25d422cc23b44c3bbd7a66c76d52af73
md5sum 25d422cc23b44c3bbd7a66c76d52af74
md5sum 25d422cc23b44c3bbd7a66c76d52af75
md5sum 25d422cc23b44c3bbd7a66c76d52af76
导致
md5sum 25d422cc23b44c3bbd7a66c76d52af46 4
md5sum 25d422cc23b44c3bbd7a66c76d52af47 5
md5sum 25d422cc23b44c3bbd7a66c76d52af48 6
md5sum 25d422cc23b44c3bbd7a66c76d52af41 8
md5sum 25d422cc23b44c3bbd7a66c76d52af22 9
md5sum 25d422cc23b44c3bbd7a66c76d52af33 12
md5sum 25d422cc23b44c3bbd7a66c76d52af12 13
md5sum 25d422cc23b44c3bbd7a66c76d52af01 16
md5sum 25d422cc23b44c3bbd7a66c76d52af55 17
md5sum 25d422cc23b44c3bbd7a66c76d52af14 19
md5sum 25d422cc23b44c3bbd7a66c76d52af18 20
md5sum 25d422cc23b44c3bbd7a66c76d52af17 23
md5sum 25d422cc23b44c3bbd7a66c76d52af77 24
md5sum 25d422cc23b44c3bbd7a66c76d52af06 25
md5sum 25d422cc23b44c3bbd7a66c76d52af05 26
md5sum 25d422cc23b44c3bbd7a66c76d52af72 27
md5sum 25d422cc23b44c3bbd7a66c76d52af73 28
md5sum 25d422cc23b44c3bbd7a66c76d52af74 29
md5sum 25d422cc23b44c3bbd7a66c76d52af75 30
md5sum 25d422cc23b44c3bbd7a66c76d52af76 31
例如如果下一个file2将具有22行/行，则它将增加数字直到32，例如]
我相信也应该通过更好的方法将file1列$ 4中的数字也放入数组并保持逻辑
awk进行救援！
$ awk 'NR==FNR{a[$NF];next} {while(++c in a); print $0, c}' file1 file2
md5sum 25d422cc23b44c3bbd7a66c76d52af46 4
md5sum 25d422cc23b44c3bbd7a66c76d52af47 5
md5sum 25d422cc23b44c3bbd7a66c76d52af48 6
md5sum 25d422cc23b44c3bbd7a66c76d52af41 8
md5sum 25d422cc23b44c3bbd7a66c76d52af22 9
md5sum 25d422cc23b44c3bbd7a66c76d52af33 12
md5sum 25d422cc23b44c3bbd7a66c76d52af12 13
md5sum 25d422cc23b44c3bbd7a66c76d52af01 16
md5sum 25d422cc23b44c3bbd7a66c76d52af55 17
md5sum 25d422cc23b44c3bbd7a66c76d52af14 20
md5sum 25d422cc23b44c3bbd7a66c76d52af18 23
md5sum 25d422cc23b44c3bbd7a66c76d52af17 24
md5sum 25d422cc23b44c3bbd7a66c76d52af77 25
md5sum 25d422cc23b44c3bbd7a66c76d52af06 26
md5sum 25d422cc23b44c3bbd7a66c76d52af05 27
md5sum 25d422cc23b44c3bbd7a66c76d52af72 28
md5sum 25d422cc23b44c3bbd7a66c76d52af73 29
md5sum 25d422cc23b44c3bbd7a66c76d52af74 30
md5sum 25d422cc23b44c3bbd7a66c76d52af75 31
md5sum 25d422cc23b44c3bbd7a66c76d52af76 32
请注意，19在您的第一个文件中，因此在输出中将其跳过。您的输出与给定输入的规格不一致。