python错误:制作可执行文件后找不到导入模块

问题描述 投票:0回答:1

Error image

from pathlib import Path
import linecache
import pyperclip
print('Looking for a path...')
print('Found path!')
Path('C:/Users/Akush/Documents/Warcraft III/CustomMapData/YouTD/')
a = linecache.getline('savecode.txt',7)
pyperclip.copy(a)
print('{} copied to clipboard!'.format(a))

因此,一切在pycharm中都可以正常工作,但是当我从.py中创建.exe时,它在CMD中给出了“找不到模块”错误

您知道我在这里做错了吗?感谢您的帮助!

python executable
1个回答
0
投票

我稍微整理了一下代码:

from pathlib import Path
import linecache
import pyperclip

# Specify the path
dir = Path('C:/Users/eramo/PycharmProjects/untitled1')
# Specify the file
file = 'savecode.txt'

# Start Searching for Path
print('Looking for a path...')

# Check if Path exists
if dir.is_dir():
    # Set the currect working directory to the found path
    os.chdir(dir)
    # Let the user know the path has been found
    print('Found path!')
    # Check to see if the file exists
    if Path(file).is_file():
        # Get lines from file
        a = linecache.getline(file, 7)
        if a == '':
            print('Nothing found in file')
        else:
            # Copy line to clipboard
            pyperclip.copy(a)
            print(f'{a} copied to clipboard!')
    else:
        print("File not found")
else:
    print('This directory does not exist')
© www.soinside.com 2019 - 2024. All rights reserved.