如何禁用获取列描述和查询结果？ （mysql2 / promise）

Question

我正在使用mysql2/promise软件包。这是我在做什么：

  const mysql = require('mysql2/promise');
  const dbConnection = await mysql.createConnection({
    host: environment.dbUrl,
    port: '3306',
    user: environment.dbUser,
    password: environment.dbPassword,
    database: environment.db,
  });
  return (dbConnection);

  const verifications = await dbConnection.execute('SELECT * FROM verifications WHERE code = ?', [code]);
  console.log('verifications', verifications);

但是查询结果包含一堆我不需要的列描述。我该如何摆脱它们？

[ [],
  [ { catalog: 'def',
      schema: 'testdb',
      name: 'id',
      orgName: 'id',
      table: 'verifications',
      orgTable: 'verifications',
      characterSet: 63,
      columnLength: 11,
      columnType: 3,
      flags: 16899,
      decimals: 0 },
    { catalog: 'def',
      schema: 'testdb',
      name: 'code',
      orgName: 'code',
      table: 'verifications',
      orgTable: 'verifications',
      characterSet: 63,
      columnLength: 11,
      columnType: 3,
      flags: 4097,
      decimals: 0 },
    { catalog: 'def',
      schema: 'testdb',
      name: 'createdAt',
      orgName: 'createdAt',
      table: 'verifications',
      orgTable: 'verifications',
      characterSet: 63,
      columnLength: 19,
      columnType: 7,
      flags: 1152,
      decimals: 0 } ] ]

Answer 1

您可以只执行const [rows, fields]以获取相关信息

  const [rows, fields] = await dbConnection.execute('SELECT * FROM verifications WHERE code = ?', [code]);