添加两个二进制数

问题描述 投票:0回答:1

我试图通过将数字放在char数组中来主持每个数字,然后使用if条件将它们分别按每个数字进行主持。应涵盖每个结果,每个结果应保存在String result中,但整个操作的结果始终为空白。 Java调试器不工作,我不明白它为什么不工作。

import java.util.Scanner;

public class BinaryAdder {
    public static String add(String binary1, String binary2) {

        String result = "";
        char[] safea = binary1.toCharArray();
        char[] safeb = binary2.toCharArray();

        int lb1 = binary1.length() - 1;
        int lb2 = binary2.length() - 1;
        char reminder = 0;

        while (lb1 != 0 || lb2 != 0) {
            if (safea[lb1] == 0 && safeb[lb2] == 0 && reminder == 0) {
                result += "0";
                lb1--;
                lb2--;
            } else if (safea[lb1] == 1 && safeb[lb2] == 0 && reminder == 0) {
                result += "1";
                lb1--;
                lb2--;
            } else if (safea[lb1] == 1 && safeb[lb2] == 1 && reminder == 0) {
                result += "0";
                reminder = 1;
                lb1--;
                lb2--;
            } else if (safea[lb1] == 1 && safeb[lb2] == 1 && reminder == 1) {
                result += "1";
                reminder = 1;
                lb1--;
                lb2--;
            } else if (safea[lb1] == 1 && safeb[lb2] == 0 && reminder == 1) {
                result += "0";
                reminder = 1;
                lb1--;
                lb2--;
            } else if (safea[lb1] == 0 && safeb[lb2] == 1 && reminder == 1) {
                result += "0";
                reminder = 1;
                lb1--;
                lb2--;
            } else if (safea[lb1] == 0 && safeb[lb2] == 1 && reminder == 0) {
                result += "1";
                lb1--;
                lb2--;
            } else if (safea[lb1] == 0 && safeb[lb2] == 0 && reminder == 1) {
                result += "1";
                lb1--;
                lb2--;
            }
        }
        return result;
    }

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        System.out.print("Summand:  ");
        String input1 = scan.next("(0|1)*");
        System.out.print("Summand:  ");
        String input2 = scan.next("(0|1)*");
        scan.close();
        System.out.println("Result: " + add(input1, input2));
    }

}
java binary addition
1个回答
1
投票

您可以使用Integer.parseInt(s, radix)将这些位解析为整数。你需要使用2的基数:

public static String add(String binary1, String binary2) {
    int i1 = Integer.parseInt(binary1, 2);
    int i2 = Integer.parseInt(binary2, 2);
    return Integer.toBinaryString(i1 + i2);
}
© www.soinside.com 2019 - 2024. All rights reserved.