我在我的游戏中制作了一个耐久性系统，但它不起作用[重复]

Question

这个问题在这里已有答案：

• Int division: Why is the result of 1/3 == 0? 15个答案

我试图这样做，以便每当你攻击敌人时，你的剑使用1耐久性，你的剑的伤害取决于剑的耐久性％

问题是它一直说sword.getDamage（）= 0.0

主要课程：

public static void main(String args[]) {
    Scanner in = new Scanner(System.in);
    Random random = new Random();
    String enemy = null;
    String input;
    Sword sword = new Sword(1, 10000, "Training Sword");
    Dictionary<String, Attributes> OneToTen = new Hashtable<String, Attributes>();
    OneToTen.put("Zombie", new Attributes(12, 11, 10, 0, 0, 4, 5, 0));
    OneToTen.put("Wizard", new Attributes(5, 6, 4, 15, 15, 10, 10, 10));
    OneToTen.put("Spider", new Attributes(7, 7, 7, 4, 6, 15, 16, 3));
    int TotalDamageDone = 0;
    int enemyNum = random.nextInt(3);
    if (enemyNum == 0) {
        enemy = "Zombie";
    } else if (enemyNum == 1) {
        enemy = "Wizard";
    } else if (enemyNum == 2) {
        enemy = "Spider";
    }
    System.out.println("Welcome to the Dungeon Of Doom \nYour enemy is a " + enemy + " it has " + (OneToTen.get(enemy).Constitution * 10) + " health. Good Luck!");
    System.out.println("What do you want to do?");
    System.out.println("I for Inventory, A for Attack, or S for Spell!");
    System.out.print(" >>>");
    input = in.nextLine();
    if (input.equals("A")) {
        System.out.println("You hit the " + enemy + " for " + sword.getDamage() + " damage.");
        sword.subtractDurability(1);
    }
}

}

剑类：

public class Sword {

int BaseDamage;
int BaseDurability;
int Durability;
double DurabilityPercentage;
int Damage;
String Name;

public Sword(int damage, int durability, String name) {
    BaseDamage = damage;
    BaseDurability = durability;
    Durability = BaseDurability;
    updateDamage();
    Name = name;
}

public void updateDamage() {
    DurabilityPercentage = (1 / BaseDurability) * Durability;
    Damage = (int) Math.round( (double) (BaseDamage * DurabilityPercentage) + 0.499999);
}

public double getDurability() {
    updateDamage();
    return DurabilityPercentage;
}

public void subtractDurability(int durability) {
    Durability -= durability;
    updateDamage();
}

public double getDamage() {
    updateDamage();
    return Damage;
}
}

属性类只有变量：

• 强度
• 宪法
• 耐力
• 智慧
• 情报
• 敏捷
• 灵巧
• 魅力

大多数变量尚未使用

Answer 1

DurabilityPercentage = (1 / BaseDurability) * Durability;

BaseDurability是一个int，所以计算1 / BaseDurability是用整数算术完成的，它将它截断为0.使1.0强制浮点运算。

DurabilityPercentage = (1.0 / BaseDurability) * Durability;