使用 faker 生成性别的最佳方式是什么，生成一个名称以使性别与名称相匹配
return [
'name' => $faker->name,
'email' => $faker->safeEmail,
'username' => $faker->userName,
'phone' => $faker->phoneNumber,
'gender' => $faker->randomElement(['male', 'female']),//the gender does not match the name as it is.
'address' => $faker->address,
'dob' => $faker->date($format = 'Y-m-d', $max = 'now'),
'password' => bcrypt('secret')
];
查看文档和 Github 问题部分提出的问题，您的解决方案似乎是最好的。有些方法允许您指定名称的性别，因此您可以这样做：
$gender = $faker->randomElement(['male', 'female']);
return [
'name' => $faker->name($gender),
'email' => $faker->safeEmail,
'username' => $faker->userName,
'phone' => $faker->phoneNumber,
'gender' => $gender,
'address' => $faker->address,
'dob' => $faker->date($format = 'Y-m-d', $max = 'now'),
'password' => bcrypt('secret')
];
希望这符合您的要求。
要在没有额外变量的情况下做到这一点，请像这样做
return [
'gender' => $faker->randomElements(['male', 'female']),
'name' => $faker->name(function (array $user) {return $user['gender'];})
]
希望有帮助
方法 randomElements 将返回一个包含单个元素的数组，因此如果您想获取“女性”或“男性”，请不要忘记在第一行末尾添加：[0] 。您需要结果数组（只有一个元素）的第一个元素（索引 0）。
$gender = $faker->randomElements(['male', 'female'])[0];
还有一件事。为了准确获得您想要的内容，您需要使用 firstName 而不是 name。这样，名字就会根据性别而定。这样做：
return [
'name' => $faker->firstName($gender),
'email' => $faker->safeEmail,
'username' => $faker->userName,
'phone' => $faker->phoneNumber,
'gender' => $gender,
'address' => $faker->address,
'dob' => $faker->date($format = 'Y-m-d', $max = 'now'),
'password' => bcrypt('secret')
];
最后一件事：如果你使用“男性”和“女性”，而不是“男性”和“女性”，这是不会起作用！！
其实所有的答案都对我来说并不真正有用。它只返回雌性或雄性。 我有几乎同样的问题。我需要从三种性别中随机选择一个元素👍😀。它总是给我这个错误消息：
Illuminate\Database\QueryException : Array to string conversion (SQL: insert
into `users` (`name`, `gender`, `email`, `admin`, `author`, `password`,
`remember_token`) values (Margaret Robel I, male, [email protected], 1, 0,
dummylogin, gwKdVN7zYv))
at /Users/mangrove/Desktop/php-workspace/laravel-
mangrove/vendor/laravel/framework/src/Illuminate/Database/Connection.php:664
660| // If an exception occurs when attempting to run a query, we'll
format the error
661| // message to include the bindings with SQL, which will make this
exception a
662| // lot more helpful to the developer instead of just the
database's errors.
663| catch (Exception $e) {
> 664| throw new QueryException(
665| $query, $this->prepareBindings($bindings), $e
666| );
667| }
668|
Exception trace:
1 ErrorException::("Array to string conversion")
/Users/mangrove/Desktop/php-workspace/laravel-
mangrove/vendor/laravel/framework/src/Illuminate/Database/
MySqlConnection.php:80
2 PDOStatement::bindValue()
/Users/mangrove/Desktop/php-workspace/laravel-
mangrove/vendor/laravel/framework/src/Illuminate/
Database/MySqlConnection.php:80
查看了 Faker v.1.8.0
的文档后这对我有用：
public function run()
{
$faker = Faker::create();
foreach(range(1,10) as $index){
// Returns always random genders according to the name, inclusive mixed !!
$gender = $faker->randomElement($array = array('male','female','mixed'));
DB::table('users')->insert([
'name' => $faker->name($gender),
'gender' => $gender,
'email' => $faker->unique()->safeEmail,
'admin' => $faker->numberBetween($min = 0, $max = 1),
'author'=> $faker->numberBetween($min = 0, $max = 1),
'password' => 'dummylogin',
'remember_token' => str_random(10),
]);
}
}
It turns out mixed genders will always have different names, because you can
be either way 😄⚧
接受的答案工作正常，但我们可以简化一些事情，而不必先设置变量
return [
'first_name' => fn(array $attributes) => fake()->firstName($attributes['gender']),
'gender' => fake()->randomElement(['male', 'female'])
],
如您所见，这样做时属性顺序并不重要
快乐编码:)
https://laravel.com/docs/10.x/eloquent-factories#defining-relationships-within-factories
如果关系的列取决于定义它的工厂 您可以将闭包分配给属性。关闭将收到 工厂评估的属性数组：