C ++中的复合类型，const和auto

Question

我试图理解这段代码。我一直在弄清楚为什么d和e是int*和const int*。我可以使用一些帮助。

const int ci = i, &cr = ci;
auto b = ci; // b is an int (top-level const in ci is dropped)
auto c = cr; // c is an int (cr is an alias for ci whose const is top-level)
auto d = &i; // d is an int*(& of an int object is int*)
auto e = &ci; // e is const int*(& of a const object is low-level const)

Answer 1

&i的意思是“取i的地址”。由于i是int，&i的类型是int*。由于d，int*的类型被推断为automatic type deduction rules。

同样的推理可以适用于ci。唯一的区别是const资格赛。