[基本上,我正在寻求一种优化此代码的方法。我想将其减少到几行,因为它对每次单击绑定都执行相同的操作。
$("#arch-of-triumph-button").click(function(){
$("#arch-of-triumph-info").addClass("active-info")
});
$("#romanian-athenaeum-button").click(function(){
$("#romanian-athenaeum-info").addClass("active-info")
});
$("#palace-of-parliament-button").click(function(){
$("#palace-of-parliament-info").addClass("active-info")
});
是否有可能将“凯旋门”,“罗马尼亚雅典剧院”,“议会宫”存储到数组中并将其拉入单击绑定?我在想一些级联吗?
$("+landmarkName+-button").click(function(){
$("+landmarkName+-info").addClass("active-info")
});
甚至有可能这样吗?预先感谢您的所有回答。
编辑:这是完整的HTML。
<div class="landmark-wrapper">
<div class="page-content landmark">
<div class="heading span-after">
<span>Arch of Triumph</span>
</div>
<div class="landmark-button" id="arch-of-triumph-button"></div>
</div>
</div>
<div class="landmark-wrapper">
<div class="page-content landmark">
<div class="heading span-after">
<span>Romanian Athenaeum</span>
</div>
<div class="landmark-button" id="romanian-athenaeum-button"></div>
</div>
</div>
----------------------------------------------------------
<div class="landmarks-info-wrapper">
<div class="landmark-info" id="arch-of-triumph-info">
<div class="info-landmark section">
<span class="landmark-title">Arch of Triumph</span>
<span class="landmark-coord">44°28′1.99″N 26°4′41.06″E</span>
</div>
</div>
<div class="landmark-info" id="romanian-athenaeum-info">
<div class="info-landmark section">
<span class="landmark-title">The Romanian Athenaeum</span>
<span class="landmark-coord">44.4413°N 26.0973°E</span>
</div>
</div>
假设您无法修改HTML标记(在这种情况下,使用CSS类会更干净),那么您的问题的解决方案如下所示:
// Assign same click handler to all buttons
$("#arch-of-triumph-button, #romanian-athenaeum-button, #palace-of-parliament-button")
.click(function() {
// Extract id of clicked button
const id = $(this).attr("id");
// Obtain corresponding info selector from clicked button id by replacing
// last occurrence of "button" pattern with info.
const infoSelector = "#" + id.replace(/button$/gi, "info");
// Add active-info class to selected info element
$(infoSelector).addClass("active-info");
});
因为每个.landmark-button
看上去都与其相关的.landmark-info
顺序相同,所以您可以将两个集合放入一个数组中,然后单击一个集合,只需在另一个数组中找到具有相同索引的元素即可:
const buttons = [...$('.landmark-button')];
const infos = [...$('.landmark-info')];
$(".landmark-button").click(function() {
const i = buttons.indexOf(this);
$(infos[i]).addClass('active-info');
});
这完全不依赖于ID-随意将它们从HTML中完全删除以变得混乱,因为它们现在不被用作选择器,因此它们没有任何作用。
实时代码段:
const buttons = [...$('.landmark-button')];
const infos = [...$('.landmark-info')];
$(".landmark-button").click(function() {
const i = buttons.indexOf(this);
$(infos[i]).addClass('active-info');
});
.active-info {
background-color: yellow;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="landmark-wrapper">
<div class="page-content landmark">
<div class="heading span-after">
<span>Arch of Triumph</span>
</div>
<div class="landmark-button" id="arch-of-triumph-button">click</div>
</div>
</div>
<div class="landmark-wrapper">
<div class="page-content landmark">
<div class="heading span-after">
<span>Romanian Athenaeum</span>
</div>
<div class="landmark-button" id="romanian-athenaeum-button">click</div>
</div>
</div>
----------------------------------------------------------
<div class="landmarks-info-wrapper">
<div class="landmark-info" id="arch-of-triumph-info">
<div class="info-landmark section">
<span class="landmark-title">Arch of Triumph</span>
<span class="landmark-coord">44°28′1.99″N 26°4′41.06″E</span>
</div>
</div>
<div class="landmark-info" id="romanian-athenaeum-info">
<div class="info-landmark section">
<span class="landmark-title">The Romanian Athenaeum</span>
<span class="landmark-coord">44.4413°N 26.0973°E</span>
</div>
</div>
较旧的答案,不知道HTML:您可以提取所单击按钮的ID,将其button
部分切开,然后选择与-info
串联在一起的按钮:
$(".landmark-button").click(function() {
const infoSel = this.id.slice(0, this.id.length - 6) + 'info';
$(infoSel).addClass('active-info');
});
不过,考虑到HTML,可能会有更优雅的解决方案。