石头、剪刀、布。打结的问题。 （蟒蛇）

Question

我按照指南制作了一个石头剪刀布游戏。一切都很顺利，但教程中没有包含平局的方法。我以为我自己可以做到这一点，但我编写的代码不起作用。我对编码非常陌生，所以我无法意识到我做错了什么。

我认为这段代码可以工作，但它只是打印玩家输给计算机时的文本。这是代码。

import random

uw = 0
cpw = 0

options = ["rock", "paper", "scissors"]

while True:
    uinput = input("Type Rock/Paper/Scissors or Q to quit: ").lower()
    if uinput == "q":
        break

    if uinput not in options:
        continue

    rn = random.randint(0, 2)
    #rock: 0, paper: 1, scissors: 2
    cpp = options[rn]
    print("Computer picked", cpp + ".")

    if uinput == "rock" and cpp == "scissors":
        print("You won!")
        uw += 1

    elif uinput == "paper" and cpp == "rock":
        print("You won!")`
        uw += 1

    elif uinput == "scissors" and cpp == "paper":
        print("You won!")
        uw += 1
    elif uinput "paper" and cpp == "paper":
        print("It's a tie, no points.")
    
    elif uinput "rock" and cpp == "rock":
        print("It's a tie, no points.")
    
    elif uinput "scissors" and cpp == "scissors":
        print("It's a tie, no points.")
    
    else:
        print("You lost!")
        cpw += 1


print("You won", uw, "times.")
print("The computer won", cpw, "times")
print("Goodbye")

Answer 1

您没有将领带行与字符串进行比较：

    elif uinput "paper" and cpp == "paper":
        print("It's a tie, no points.")

应该是：

elif uinput == "paper" and cpp == "paper":
    print("It's a tie, no points.")

这里，您的代码中缺少

==

，这就是检查您的

uinput

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